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how to convert and use 1 bit hex-number using COBOL


IBM Mainframe Forums -> COBOL Programming
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anonguy456

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Joined: 29 Jun 2021
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PostPosted: Wed Sep 22, 2021 9:22 pm
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how to convert a 1 bit hex number to decimal form, or at least use it for some mathematical operation.

the problem is that this 1 bit hex number can be viewed only in hex form that too after turning hex on in the file.

the maximum hex value that will be present in 1 bit is FF which is 255 in decimal.

please guide.
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dneufarth

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PostPosted: Wed Sep 22, 2021 9:33 pm
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I believe that is a 1 byte number in packed decimal.

X’1F’. F may be interpreted as unsigned and may be interpreted as positive.
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Joerg.Findeisen

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PostPosted: Wed Sep 22, 2021 9:37 pm
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As always:

What is your input, desired output. If you follow the forum you should know how it works. Attachments in general will not be read.
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anonguy456

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PostPosted: Wed Sep 22, 2021 9:49 pm
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hey dneufarth, this 1F is considered as 31 only.

the thing is i am not able to convert this 1F to 31.
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dneufarth

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PostPosted: Wed Sep 22, 2021 10:55 pm
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Try reading this

ibmmainframes.com/about41628.html
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anonguy456

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PostPosted: Thu Sep 23, 2021 12:09 am
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dneufarth wrote:
Try reading this

ibmmainframes.com/about41628.html


This approach wont work in my case as the approach you suggested is the one using JCLs.

In my case at certain intervals (not fixed) i am supposed to read this hex values.
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dneufarth

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PostPosted: Thu Sep 23, 2021 12:09 am
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Please move to COBOL forum.
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anonguy456

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PostPosted: Thu Sep 23, 2021 12:10 am
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[quote="anonguy456"]
dneufarth wrote:
Try reading this

ibmmainframes.com/about41628.html


This approach wont work in my case as the approach you suggested is the one using JCLs.

In my case at certain intervals (not fixed) i am supposed to read this hex values from an input file.
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sergeyken
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Joined: 29 Apr 2008
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PostPosted: Thu Sep 23, 2021 1:39 am
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anonguy456 wrote:

This approach wont work in my case as the approach you suggested is the one using JCLs.

Please, learn carefully the difference between JCL, COBOL, and system utilities.

Before that, it does not make sense to discuss ANY issue.
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Robert Sample

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Joined: 06 Jun 2008
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Location: Dubuque, Iowa, USA

PostPosted: Thu Sep 23, 2021 2:53 am
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The first thing to know is that the term "bit" refers to a single 0/1 value -- there are 8 bits to a byte, and a byte is what you are calling a bit. Bit is short for binary digit. So terminology is your first, and a very major, issue.

Second, it is EASY to use hex bytes for arithmetic in COBOL. Define a COBOL group variable with 2 1-byte variables in the group. REDEFINE the group to be a half-word binary value (COMP-5 although COMP will also work; COMP-1, COMP-2, COMP-3 are not suitable for this). Move LOW-VALUES to your group variable. Move your hex variable to the second byte of the group variable. Use the REDEFINE variable as a numeric value for whatever you want to do with it.
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anonguy456

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PostPosted: Sat Sep 25, 2021 8:58 am
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Robert Sample wrote:
The first thing to know is that the term "bit" refers to a single 0/1 value -- there are 8 bits to a byte, and a byte is what you are calling a bit. Bit is short for binary digit. So terminology is your first, and a very major, issue.

Second, it is EASY to use hex bytes for arithmetic in COBOL. Define a COBOL group variable with 2 1-byte variables in the group. REDEFINE the group to be a half-word binary value (COMP-5 although COMP will also work; COMP-1, COMP-2, COMP-3 are not suitable for this). Move LOW-VALUES to your group variable. Move your hex variable to the second byte of the group variable. Use the REDEFINE variable as a numeric value for whatever you want to do with it.


Thank You Robert icon_smile.gif

Sample of code for reference:
Code:
01 WS-LENGTH.                                               
   02 WS-LENGTH1             PIC X(01).                     
   02 WS-LENGTH2             PIC X(01).                     
01 WS-CONVERTED-LENGTH REDEFINES WS-LENGTH PIC 9(02) COMP-5.
01 WS-TEMP                   PIC 9(03) VALUE 0.             
**************************************************         
PROCEDURE DIVISION.                                         
MAIN-PARA.                                                 
    MOVE LOW-VALUES TO WS-LENGTH                           
    MOVE INPUT1-RECORD(171:1) TO WS-LENGTH2                 
    PERFORM WS-CONVERTED-LENGTH TIMES                       
       ADD 1 TO WS-TEMP                                     
    END-PERFORM                                             
    DISPLAY WS-TEMP         
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