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Replace each space in cobol string with a substring.


IBM Mainframe Forums -> COBOL Programming
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Ali_gezer

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Joined: 06 Apr 2021
Posts: 123
Location: argentina

PostPosted: Sat Mar 23, 2024 2:53 am
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Hello to all.

How to remove spaces within a string in COBOL, and for each space removed, replace it with the string XXXX. That is, the characters to the right of the removed space should be retained, they just need to be moved to the right.


my requirement is:


original string
Code:
123 456 789



changed string

Code:
123xxxx456xxxx789



do you have any clue? in jcl I can use Outrec and insert the substring but in cobol I did not reach the desire result yet.

Thanks
Code'd for you
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Joerg.Findeisen

Senior Member


Joined: 15 Aug 2015
Posts: 1269
Location: Bamberg, Germany

PostPosted: Sat Mar 23, 2024 4:51 am
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Ali_gezer wrote:
in jcl I can use Outrec and insert the substring but in cobol I did not reach the desire result yet.

JCL does not have an OUTREC keyword.
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Phrzby Phil

Senior Member


Joined: 31 Oct 2006
Posts: 1042
Location: Richmond, Virginia

PostPosted: Sat Mar 23, 2024 8:32 am
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My turn to say: With 123 posts starting 3 years ago, you must know by now that no one is going to help you until you post (using code tags) your attempted solution, along with the input and output from your latest test.
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Rohit Umarjikar

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Joined: 21 Sep 2010
Posts: 3055
Location: NYC,USA

PostPosted: Fri Mar 29, 2024 6:03 am
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You can use reference modification in COBOL.. move one by one byte to output field and once you hit the space move hardcoded 'xxxx' and continue to advance one byte to move to output field until end of record.

Does this hint help?
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