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how to find the duplicate list


IBM Mainframe Forums -> DB2
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RAVIGUPTA1990

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Joined: 24 Feb 2016
Posts: 3
Location: india

PostPosted: Wed Mar 30, 2016 12:11 am
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Hi my requirement is ,I have found out the duplicate list from the table but I need to find the list containing the names , like
Code:
MANISH
MANISH
MANISH
RAVI
RAVI


I have used the below query for my requirement

Code:
SELECT (NMFIRST||NMLAST||CHAR(DTBIRTH)||CHAR(ADEMAIL))   
  FROM TABLE                                     
GROUP BY (NMFIRST||NMLAST||CHAR(DTBIRTH)||CHAR(ADEMAIL)) 
HAVING COUNT(*)>1                                         
WITH UR;


My query is just giving me the results of the duplicate values but I need descriptive details like all the duplicates should be visible
Code:
                   MANISH
                   MANISH
                   MANISH
                   RAVI
                   RAVI


Please help.

Coded, converted to lower case and 'asap' removed
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Nic Clouston

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Joined: 10 May 2007
Posts: 2448
Location: Hampshire, UK

PostPosted: Wed Mar 30, 2016 1:28 pm
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RAVIGUPTA1990,

1 - do not SHOUT (use all upper case)
2 - use the code tags to present code, data and cut'n'paste from screen
3 - if you need ASAP hire a consultant

These have all been fixed for you - this time.


You did not show what your results were so we have no idea what you are getting at.
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RAVIGUPTA1990

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Joined: 24 Feb 2016
Posts: 3
Location: india

PostPosted: Wed Mar 30, 2016 2:53 pm
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I was not saying do it immediately ,i used please .My requirement is to get the list of duplicate values in a table with all occurences
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Nic Clouston

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Joined: 10 May 2007
Posts: 2448
Location: Hampshire, UK

PostPosted: Wed Mar 30, 2016 4:41 pm
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ASAP = As Soon As Possible
it does not mean 'please'. 'Please' means 'please'
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Robert Sample

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Joined: 06 Jun 2008
Posts: 8569
Location: Dubuque, Iowa, USA

PostPosted: Wed Mar 30, 2016 4:53 pm
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Have you thought about what a GROUP BY means in an SQL query?
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RAVIGUPTA1990

New User


Joined: 24 Feb 2016
Posts: 3
Location: india

PostPosted: Wed Mar 30, 2016 7:29 pm
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Thanks ,i have got the solution for this . icon_surprised.gif
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GuyC

Senior Member


Joined: 11 Aug 2009
Posts: 1281
Location: Belgium

PostPosted: Tue Apr 05, 2016 6:24 pm
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If your table has a primary_key :
Code:
Select * from Mytable A,
where exists( select * from Mytable B where A.some_columns  = b.some_columns and a.PK not = b.PK)
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