Get a string without leading spaces in natural

Shah · New User Joined: 05 Sep 2006 Posts: 18

Hi Folks,

I am new to NATURAL. In NATURAL programming how should i get a string without leading spaces. Is there any verb like INSPECT in COBOL.

Thanks,
Shah

ofer71 · Posted: Wed Nov 29, 2006 1:01 am

Yes, the equivalent in NATURAL is EXAMINE.

O.

Shah · New User Joined: 05 Sep 2006 Posts: 18

Hi Ofer71,

Thanks for that. I need some more info. I have a question.

Question:

I have a string variable ABC (A79), this is initialized with 20 characters. While displaying this variable i am getting 59 spaces and the string is displaying from 60th position. How can i remove the spaces.

My target is while display i need only 20 characters (Means with out spaces).

Thanks in advance,
Shah

ofer71 · Posted: Wed Nov 29, 2006 11:51 am

Shah -

before the display, add the following statement (assuming your variable name is ABC):

Shah · New User Joined: 05 Sep 2006 Posts: 18

Ofer,

Thanks , i will try this and let you know.

Thanks,
shah

Shah · New User Joined: 05 Sep 2006 Posts: 18

Ofer,

I got that but not exactly. i need some more info. As per your EXAMINE verb, her i am getting first 20 characters following spaces. Now my requirement is, output will be only text without spaces.

Please help.

Thanks in advance,
Shah

ofer71 · Posted: Wed Nov 29, 2006 8:31 pm

You can find the ending position of the string after the EXAMINE, but that won't help you, since NATURAL always pad variables with blanks.

O.