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String has hex character need to convert it to decimal


IBM Mainframe Forums -> COBOL Programming
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ndilipan

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Joined: 11 Aug 2022
Posts: 2
Location: Netherlands

PostPosted: Thu Aug 11, 2022 11:34 pm
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Hello,

I have a field which is declared as pic x(08) contains character.

01 WS-Date PIC X(08).

Having string value 52B30011 direct string not stored as hexadecimal . I want to convert this into decimal/integer value.

Expected value : 1387462673

Thanks in advance.
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Robert Sample

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Joined: 06 Jun 2008
Posts: 8696
Location: Dubuque, Iowa, USA

PostPosted: Fri Aug 12, 2022 12:48 am
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This is a HELP forum, not a WRITE-THE-CODE-FOR-YOU forum. Once you've worked out the logic you need, if you have problems then you can post what the issue(s) are.

Hint: use reference modification to isolate each character, evaluate its value and multiply that value by the appropriate power of 16 and accumulate those values.
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ndilipan

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Joined: 11 Aug 2022
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Location: Netherlands

PostPosted: Fri Aug 12, 2022 12:56 am
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Hello Robert,

Thank you so much, I have written that logic multiplying by 16 with power sorry for not posting that in prior. I have posted to check, is there any function we can do it.

Thanks again!! icon_smile.gif
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Robert Sample

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Location: Dubuque, Iowa, USA

PostPosted: Fri Aug 12, 2022 2:14 am
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No, there is no function to do what you want. Intrinsic function HEX-TO-CHAR converts a hexadecimal value to a character string, but you already have the character string. And the NUMVAL intrinsic functions don't work on hexadecimal values, just decimal ones.
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