converting BI to ZD

Simma Hemanth · New User Joined: 05 Jul 2021 Posts: 7 Location: India

Hi,

let me explain my question,

i have a COMP S9(9) length-4 value -803 . now i have convert this comp variable to character ZD.

My Expected output:
is same as above i/p value -803

Code:

sergeyken · Posted: Thu Jul 15, 2021 7:26 pm

0) there is no such format in COBOL - “S9(9) length-4”

1) learn how to use code tags in your post

2) how do you expect the value (F’-803’ in Assembler) to look like after TO=ZDF - ???

3) read the SORT manual about the conversion TO=ZDF. You’ve got exactly what is described.

4) why not to run several tests with several options and values, to find out by yourself: what is wrong in your mind?

Simma Hemanth · New User Joined: 05 Jul 2021 Posts: 7 Location: India

Hi Sergeyken,

the field name contains picture of S9(9) COMP. , its length is 4 and it contains value -803.

this field have to be converted from comp to character
For this first I have coded as ,

sergeyken · Posted: Thu Jul 15, 2021 7:54 pm

I see, you refuse to read the SORT manual about TO=ZDF…

Using BI instead of FI demonstrates that you did not read about those values, too

Hint: use parameter EDIT=(…), or Mxx - whatever you prefer

Try to run different tests with different values, and different options, to train your mind in understanding the whole picture

Rohit Umarjikar · Posted: Thu Jul 15, 2021 9:07 pm

This is a very basic question and discussed several times on this board , please learn to use SEARCH to find relevant topics then try and if doesn't work then post back with sample data , errors , code which you tried.
ibmmainframes.com/about34882.html
ibmmainframes.com/about46967.html

sergeyken · Posted: Thu Jul 15, 2021 11:31 pm

Nowadays, any admonition to begin learning something does not help...
Without a ready-to-use answer there is not a minor step forward

First of all, one needs to understand well the existing data formats, and the rules of their conversion. Something like this example: