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vinkum
New User
Joined: 20 Sep 2019 Posts: 2 Location: INDIA
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Hi,
I am trying to use SFTPPROC to transfer files from X LPAR to Y LPAR, I need help in allocating the space parameter to transfer the file successfully.
My SFTP process fails due to space parameter-which i have not allocated it correctly.
FILE A : SPACE=(27930,(500,50),RLSE) (On X LPAR)
to be transferred to Y LAPR using SFTPPROC with below options
ls /+lrecl=133,recfm=fbm,space=cyl.500.50,unit=DDDD
Can someone help me to convert (27930,(500,50),RLSE) to tracks/cyl?
I need to be precise with the allocation of the files being transferred, Job failed in prod when i gave random allocations due to excessive or less space allocated.I have multiple files defined in BLKSIZE which need to be transferred via SFTP process,So i need to provide appropriate allocations.
Thanks in advance!! |
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steve-myers
Active Member
Joined: 30 Nov 2013 Posts: 917 Location: The Universe
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BLKSIZE=27930 equates to 2 records per track.
Emulated 3390 devices always have 15 emulated tracks per emulated cylinder.
Remember these lines.
so SPACE=(27930,500) becomes the equivalent of SPACE=(TRK,(13965,250))
or SPACE=(CYL,(931,17))
27930/2 = 13965 500/2 = 250 13965/15 = 931 250/15 =17 |
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Marso
REXX Moderator
Joined: 13 Mar 2006 Posts: 1353 Location: Israel
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steve-myers wrote: |
BLKSIZE=27930 equates to 2 records per track. |
I believe that you meant 2 blocks per track. |
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steve-myers
Active Member
Joined: 30 Nov 2013 Posts: 917 Location: The Universe
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2 physical records per track, which, of course, is the same as 2 blocks. |
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