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dudenithy
New User
Joined: 02 Mar 2012
Posts: 48
Location: India
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Hello all,
I would like to know is there any efficient way of matching a value against a Parameter with multiple Wildcard mask "*"? For Parameter with multiple wildcard characters "?", and for a parameter with single symbol "*", it is simple. Now I have a challenge to cater multiple "*" in a parameter.
Example: 12*5*78. Values with 12578, 123578, 12345678 are accepted, but not like 123478, 125789, 1234567. Wildcard Symbol can be placed at any place of a value (*1234*, 12*5*78*9*, etc).
I have tried checking the efficient pseudo code, but couldn't get it  .
Could anyone help or suggest? Thanks. |
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dudenithy
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Joined: 02 Mar 2012
Posts: 48
Location: India
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Thanks for the above suggestions. Too simple, but unfortunately I cannot use it, since I have to do it in COBOL only  .
I'm trying to build the logic in COBOL. This will work to a extent with some complicated Wildcard combinations must be restricted in Parameters. I will post when ready.
In the meantime, if anyone already smart have a logic in COBOl, always be welcome  . |
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Rohit Umarjikar
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Joined: 21 Sep 2010
Posts: 3076
Location: NYC,USA
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| Quote: |
Thanks for the above suggestions. Too simple, but unfortunately I cannot use it, since I have to do it in COBOL only.
I'm trying to build the logic in COBOL. This will work to a extent with some complicated Wildcard combinations must be restricted in Parameters. I will post when ready.
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May we know why? But then did you understand both the logic? What in cobol doesn't let you mimic the above logic? |
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dudenithy
New User
Joined: 02 Mar 2012
Posts: 48
Location: India
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| Rohit Umarjikar wrote: |
| May we know why? But then did you understand both the logic? What in cobol doesn't let you mimic the above logic? |
It is because I'm not fit enough to understand all commands of above programming languages (though I could able to fairly understand the logic concept) and as said already, in between I'm mid of developing the code in COBOL itself. |
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dudenithy
New User
Joined: 02 Mar 2012
Posts: 48
Location: India
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Hello all again,
Good News.. I believe I have done the Wildcard logic process in COBOL itself . Please find the code below. This should work according to below restrictions:
1. Wildcard Symbol * shouldn't occur continuously. 2. Wildcard symbols * and ? shouldn't occur contiuously.
You are much appreciated to correct me if you find something which can be done efficiently or logic holes any.
| Code: |
FD INPUT-FILE
RECORDING MODE IS F BLOCK CONTAINS 0 RECORDS.
01 IN-RECORD.
05 WS-STRING PIC X(20).
05 FILLER PIC X(30).
*
WORKING-STORAGE SECTION.
01 WS-DATA.
03 EOF PIC X(01) VALUE 'N'.
* PARAMETER WITH / WITHOUT WILDCARD SYMBOLS '*' '?'
* 03 PARM PIC X(20) VALUE '*345'.
* 03 PARM PIC X(20) VALUE '*ES'.
* 03 PARM PIC X(20) VALUE '123*'.
* 03 PARM PIC X(20) VALUE 'PAY PAL*'.
* 03 PARM PIC X(20) VALUE '*AL SER*'.
* 03 PARM PIC X(20) VALUE 'E?AY?SE?'.
03 PARM PIC X(20) VALUE '*L SERV?C* LT?'.
* CHARACTERS AFTER WILDCARD * IN PARAMETER
03 PART1 PIC X(20).
* CHARACTERS AFTER WILDCARD * BUT BEFORE ? IN PARAMETER
03 PART2 PIC X(20).
* LENGTH OF PART1
03 WS-PART1 PIC 9(02) VALUE 0.
* LENGTH OF PART2
03 WS-PART2 PIC 9(02) VALUE 0.
* COUNT FOR WILDCARD '?'
03 WS-Q PIC 9(02) VALUE 0.
* COUNT FOR WILDCARD '*'
03 WS-A PIC 9(02) VALUE 0.
* STRING BYTE REFERENCE
03 WS-I PIC 9(02) VALUE 0.
* PARAMETER BYTE REFERENCE
03 WS-J PIC 9(02) VALUE 0.
* PARM LENGTH UNTIL NEXT WILDCARD
03 WS-K PIC 9(02) VALUE 0.
* PARM LENGTH EXCL.TRAILING SPACES WHEN NO MORE WILDCARDS
03 WS-L PIC 9(02) VALUE 0.
* MATCHING PARM CHARS AFTER WILDCARD * AGAINST INPUT STRING
03 WS-MATCH-FND PIC X(01) VALUE ' '.
88 MATCH-FND VALUE 'Y'.
* RESULT
03 WS-COMPARE-FLAG PIC X(01) VALUE ' '.
88 WS-COMPARE-TRUE VALUE 'Y'.
88 WS-COMPARE-FALSE VALUE 'N'.
*
PROCEDURE DIVISION.
*
0000-MAIN-CONTROL.
PERFORM 0100-MAIN-CONTROL
GOBACK
.
*
0100-MAIN-CONTROL.
INSPECT PARM TALLYING WS-Q FOR ALL '?'
INSPECT PARM TALLYING WS-A FOR ALL '*'
*
OPEN INPUT INPUT-FILE
*
READ INPUT-FILE
AT END MOVE 'Y' TO EOF
END-READ
*
PERFORM UNTIL EOF = 'Y'
MOVE SPACE TO WS-COMPARE-FLAG
MOVE ZEROS TO WS-I
WS-J
WS-L
*
EVALUATE TRUE ALSO TRUE
WHEN WS-Q = 0 ALSO WS-A = 0
IF PARM IS EQUAL WS-STRING
SET WS-COMPARE-TRUE TO TRUE
ELSE
SET WS-COMPARE-FALSE TO TRUE
END-IF
WHEN OTHER
PERFORM COMPLEX-LOGIC
IF NOT WS-COMPARE-TRUE AND NOT WS-COMPARE-FALSE
SET WS-COMPARE-TRUE TO TRUE
END-IF
END-EVALUATE
*
READ INPUT-FILE
AT END MOVE 'Y' TO EOF
NOT AT END
IF WS-STRING IS EQUAL SPACES
MOVE 'Y' TO EOF
END-IF
END-READ
END-PERFORM
*
CLOSE INPUT-FILE
.
*
COMPLEX-LOGIC.
MOVE 1 TO WS-I
WS-J
PERFORM UNTIL WS-COMPARE-TRUE OR WS-COMPARE-FALSE OR
WS-I > LENGTH OF WS-STRING OR
WS-J > LENGTH OF WS-STRING
EVALUATE TRUE
WHEN PARM (WS-J:1) = '?'
ADD 1 TO WS-I
WS-J
SUBTRACT 1 FROM WS-Q
WHEN PARM (WS-J:1) = WS-STRING (WS-I:1) AND
PARM (WS-J:1) NOT = '*'
ADD 1 TO WS-I
WS-J
WHEN (PARM (WS-J:1) NOT = WS-STRING (WS-I:1) AND
PARM (WS-J:1) NOT = '*')
SET WS-COMPARE-FALSE TO TRUE
WHEN PARM (WS-J:1) = '*' AND
PARM (WS-J + 1:) = SPACES
SET WS-COMPARE-TRUE TO TRUE
WHEN OTHER
ADD 1 TO WS-J
SUBTRACT 1 FROM WS-A
UNSTRING PARM(WS-J:) DELIMITED BY '*'
INTO PART1 COUNT IN WS-PART1
END-UNSTRING
*
IF WS-A = 0
INSPECT FUNCTION REVERSE(PART1)
TALLYING WS-L FOR LEADING SPACES
COMPUTE WS-L = LENGTH OF PART1 - WS-L
MOVE WS-L TO WS-PART1
END-IF
*
IF WS-Q > 0
UNSTRING PART1 DELIMITED BY '?'
INTO PART2 COUNT IN WS-PART2
END-UNSTRING
MOVE WS-PART2 TO WS-PART1
END-IF
*
MOVE SPACE TO WS-MATCH-FND
COMPUTE WS-K = LENGTH OF WS-STRING -
WS-PART1 + 1
PERFORM UNTIL MATCH-FND OR WS-K < WS-I
IF WS-STRING(WS-K:WS-PART1) =
PART1(1:WS-PART1)
SET MATCH-FND TO TRUE
COMPUTE WS-I = WS-K + WS-PART1
COMPUTE WS-J = WS-J + WS-PART1
ELSE
SUBTRACT 1 FROM WS-K
END-IF
END-PERFORM
IF NOT MATCH-FND
SET WS-COMPARE-FALSE TO TRUE
END-IF
END-EVALUATE
END-PERFORM
. |
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enrico-sorichetti
Superior Member
Joined: 14 Mar 2007
Posts: 10888
Location: italy
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| Quote: |
1. Wildcard Symbol * shouldn't occur continuously.
2. Wildcard symbols * and ? shouldn't occur contiuously.
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if ...
* stands for 0 or more chars
? stands for one char
a combination ?* is legal ... it requests for at last one char
anyway unless You want to be pedantic
if the pattern analysis is done properly
any mix of * and ? should work... |
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Robert Sample
Global Moderator
Joined: 06 Jun 2008
Posts: 8700
Location: Dubuque, Iowa, USA
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Since your COMPLEX-LOGIC changes the values of WS-Q and WS-A, you need to place
| Code: |
INSPECT PARM TALLYING WS-Q FOR ALL '?'
INSPECT PARM TALLYING WS-A FOR ALL '*' |
inside the PERFORM loop or you'll get invalid results for all input records after the first one. |
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enrico-sorichetti
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Joined: 14 Mar 2007
Posts: 10888
Location: italy
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I suggest to implement a simpler - MORE UNDERSTANDABLE - logic ...
in two weeks changing something in the current approach will be a nightmare |
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dudenithy
New User
Joined: 02 Mar 2012
Posts: 48
Location: India
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| Robert Sample wrote: |
Since your COMPLEX-LOGIC changes the values of WS-Q and WS-A, you need to place
| Code: |
INSPECT PARM TALLYING WS-Q FOR ALL '?'
INSPECT PARM TALLYING WS-A FOR ALL '*' |
inside the PERFORM loop or you'll get invalid results for all input records after the first one. |
Agreed. Indeed I had INSPECT inside each file record read process during my testing. But when putting into forum, I simplified the code not to becoming too big  . |
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dudenithy
New User
Joined: 02 Mar 2012
Posts: 48
Location: India
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| enrico-sorichetti wrote: |
I suggest to implement a simpler - MORE UNDERSTANDABLE - logic ...
in two weeks changing something in the current approach will be a nightmare |
I tried to be simplifier as much I can  . Please be welcome if you could able to fine tune it . |
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enrico-sorichetti
Superior Member
Joined: 14 Mar 2007
Posts: 10888
Location: italy
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| Quote: |
| I simplified the code not to becoming too big |
when You ask people to look at Your code,
You should post it completely, not just excerpts |
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dudenithy
New User
Joined: 02 Mar 2012
Posts: 48
Location: India
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| enrico-sorichetti wrote: |
If ...
* stands for 0 or more chars
? stands for one char
a combination ?* is legal ... it requests for at last one char
anyway unless You want to be pedantic
if the pattern analysis is done properly
any mix of * and ? should work... |
Yes, the rule is absolutely right and the Standard one.
Regarding combination ?*, my logic still works. combination *? will not work. My above mentioned restriction rule must be corrected. Thanks. |
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dudenithy
New User
Joined: 02 Mar 2012
Posts: 48
Location: India
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| enrico-sorichetti wrote: |
when You ask people to look at Your code,
You should post it completely, not just excerpts |
Yes Enrico, I should have.. lessons learnt  . |
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enrico-sorichetti
Superior Member
Joined: 14 Mar 2007
Posts: 10888
Location: italy
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topic cleaned up of unsuitable solutions ...
a COBOL solution was requested.
for those who simply want to show alternative solutions in other languages
a new topic should be started with a tiltle along the lines of
'wildcard matching - REXX/C/BRAINFUCK/... whatever language ... solution' |
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