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Suganya87
New User
Joined: 09 May 2016
Posts: 12
Location: India
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Hi ,
I need ( Year + Today's Julian date ) for an example if Julian date of today is 230 then I need 2016230 as my output.
I Tried Julian_Day but it gave integer value from 1472 B.C .
Can anyone tel me how to achieve this. |
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Marso
REXX Moderator
Joined: 13 Mar 2006
Posts: 1353
Location: Israel
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Here is one possibility:
| Code: |
COMPUTE INTEGER-DATE = FUNCTION INTEGER-OF-DATE (DATE-YYYYMMDD)
COMPUTE JULIAN-DATE = FUNCTION DAY-OF-INTEGER (INTEGER-DATE) |
Shorter version:
| Code: |
COMPUTE JULIAN-DATE = FUNCTION
DAY-OF-INTEGER ( FUNCTION INTEGER-OF-DATE(DATE-YYYYMMDD) ) |
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Suganya87
New User
Joined: 09 May 2016
Posts: 12
Location: India
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Hi Marso,
Sorry I need in SQL format , not cobol code. |
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Marso
REXX Moderator
Joined: 13 Mar 2006
Posts: 1353
Location: Israel
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| Grrrrrrrrr |
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Nic Clouston
Global Moderator
Joined: 10 May 2007
Posts: 2454
Location: Hampshire, UK
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| Then why post in the COBOL programming section and not the DB2 section? Locking. |
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