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Julian Date and year


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Suganya87

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Joined: 09 May 2016
Posts: 12
Location: India

PostPosted: Wed Aug 17, 2016 6:22 pm
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Hi ,

I need ( Year + Today's Julian date ) for an example if Julian date of today is 230 then I need 2016230 as my output.

I Tried Julian_Day but it gave integer value from 1472 B.C .

Can anyone tel me how to achieve this.
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Marso

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Joined: 13 Mar 2006
Posts: 1349
Location: Israel

PostPosted: Wed Aug 17, 2016 6:55 pm
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Here is one possibility:
Code:
COMPUTE INTEGER-DATE = FUNCTION INTEGER-OF-DATE (DATE-YYYYMMDD)
COMPUTE JULIAN-DATE  = FUNCTION DAY-OF-INTEGER (INTEGER-DATE)

Shorter version:
Code:
COMPUTE JULIAN-DATE  = FUNCTION                             
    DAY-OF-INTEGER ( FUNCTION INTEGER-OF-DATE(DATE-YYYYMMDD) )
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Suganya87

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Joined: 09 May 2016
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Location: India

PostPosted: Wed Aug 17, 2016 7:01 pm
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Hi Marso,

Sorry I need in SQL format , not cobol code.
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Marso

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PostPosted: Wed Aug 17, 2016 7:25 pm
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Grrrrrrrrr
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Nic Clouston

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Joined: 10 May 2007
Posts: 2455
Location: Hampshire, UK

PostPosted: Wed Aug 17, 2016 7:38 pm
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Then why post in the COBOL programming section and not the DB2 section? Locking.
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