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Need DB2 Query by using SUBSTR


 
IBM Mainframe Forums -> DB2
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naveensrimf

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Joined: 04 Oct 2005
Posts: 34

PostPosted: Fri May 29, 2015 6:22 pm
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Hi,

Below table have account number and Information ID.

I need a query to display the Account number,Information ID where the last two digists are same in the Accounts number.


Table information given below


Table1:
------------
Account No Information ID
----------- ------------------
1000051 20001
1000061 20005
1000081 20009
2000051 20006
2000061 20007
3000051 20010
4000051 20011
6000051 20021
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Rohit Umarjikar

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Joined: 21 Sep 2010
Posts: 2503
Location: NY,USA

PostPosted: Fri May 29, 2015 9:15 pm
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Insufficient info provided by you but try for this.

Code:
select Account_No, Information_ID 
from table
where 
substr(CAST( TRANSLATE('87654321',Account_No, '12345678')AS int ),1,1) =
substr(CAST( TRANSLATE('87654321',Account_No, '12345678')AS int ),2,1)
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Nic Clouston

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Joined: 10 May 2007
Posts: 2429
Location: Hampshire, UK

PostPosted: Sat May 30, 2015 2:16 am
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I think he means where the last 2 digits of an account number match the last two digits of another account number so from the data provided that is:
1000051
2000051
3000051
4000051 and
6000051
and
1000061 and
2000061

or is it that the last 2 digits of the info_id match the last 2 digits of the account number where nothing matches?

Clarification, and example output, is required.
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mohitsaini
Warnings : 1

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Joined: 15 May 2006
Posts: 92

PostPosted: Wed Jul 01, 2015 9:25 am
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Nic - I think your former interpretation is correct. For that would the below query solve this problem?


Code:
SELECT A.Account_No, A.Information_ID  FROM TABLE A, TABLE B
WHERE SUBSTR(A.Account_No,(length(A.Account_No)-1),2) = SUBSTR(B.Account_No,(length(B.Account_No)-1),2);
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