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tecnokrat
Warnings : 1
Active User
Joined: 22 May 2009
Posts: 160
Location: Bangalore
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Hi,
I have a table with records more than 40 for each of the particular entry.
Now my program has a logic which checks for 40 occurences only in this table and then close the cursor.
But the records are more than 40 for each of these entries the flag is not set appropriately and the Cursor is not getting closed.
This is the reason when some other records are tried to fetch and the cursor never got closed.
The below query gave the total number of records having count more than 40 for each record in the table.
| Quote: |
SELECT A
from table TAB1
GROUP BY A
HAVING COUNT(*) > 40
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Now I need to tweak the query where it should delete only the record's entries from 41st and not the whole of the record.
| Quote: |
DELETE
FROM TABLE TAB1 a
WHERE a.A IN (
SELECT b.A
FROM TABLE TAB1 b
GROUP BY b.A
HAVING COUNT(*) > 40)
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Please can you help. |
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Nic Clouston
Global Moderator
Joined: 10 May 2007
Posts: 2455
Location: Hampshire, UK
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| suppose the 41st, or greater, row is the latest? DB2 does not guarantee the order in which is returns rows so you could be getting back ones thaty you would perhaps want deleted. Why not read all the records, process the 40 that you need and then issue deletes for the remining using keys that you have stored in working storage? |
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GuyC
Senior Member
Joined: 11 Aug 2009
Posts: 1281
Location: Belgium
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1) Using Olap function row_number() partition by
| Code: |
delete from tableX X where rid(x) in (
select RI from (
select row_number() over
(partition by ColA
order by ColB) as RN
,rid(A) as RI
from tableX A) B
where rn > 40 ) |
or
2) Using fetch first n Rows only in subselect
| Code: |
delete from tableX X where RID(X) not in (
select y.ri from
(select ColA from tableX group by ColA) A
, table (select rid(B) as RI from TableX B
where a.ColA = b.ColA
order by b.colB
fetch first 40 rows only) Y
) |
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