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Ambili S
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Joined: 06 Sep 2007
Posts: 112
Location: India
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Hi
The requirement is i need to use an array with ODO clause for the following case.
There are 5 managers and the no. of area each manager handles varies from 3 to 6.
I need to know how to load this array with syntax and the declaration.
and how data would be present in the input file.Also how to load this array from the file. |
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Arun Raj
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| Ambili S wrote: |
| and how data would be present in the input file |
Do you believe that somebody here knows better about YOUR input data?  |
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Ambili S
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Posts: 112
Location: India
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| The input file contains the manager id ( 2 chars) and the no of area he handles ( pic 9(1)). |
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Arun Raj
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| Is this a business requirement or some kind of case study? What do you mean by "ODO clause"? If you're referring to the COBOL OCCURS DEPENDING ON, why not read through the COBOL Manuals and try something on your own first. |
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Ambili S
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Posts: 112
Location: India
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Here's my requirement,please ignore the above posts.
I have a students file which contains student id(2 char) and the subjects ( 3 chars) they have opted for. The subjects opted by the students varies from 2 to 6. The input file is as follows :
01ENGHIN
02HINGEOCHESCIENGBIO
03SCIGEOPHYBIO
My query is how to declare this using occurs depending on clause and how do i load this array from the above file. After loading if i want to see the subjects opted by student id 02 , how can i do it. |
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dbzTHEdinosauer
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Joined: 20 Oct 2006
Posts: 6966
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you will miss the 'learning portion of this exercise'
without making any effort yourself.
so, without explanation, I will show you how to define your table.
| Code: |
05 student-count pic s9(7) comp-3 value zero.
05 student-table occurs 0 to 5000 times depending on student-count indexed by student-idx.
10 student-id pic x(02).
10 class pic x(03) occurs 6 times indexed by class-idx.
88 no-class value spaces.
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with this as a start, I will leave it to you to try your hand at the code. |
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Ambili S
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Posts: 112
Location: India
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| Thanks for the above code.If you could provide me some links which can throw more light on this , it would of great help.Meanwhile i"ll try with the piece of code you have provided. |
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dbzTHEdinosauer
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you can start with the IBM Manuals link at the top of the page.
This is a link for All Cobol Manuals. |
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Anuj Dhawan
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Ambili S
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Posts: 112
Location: India
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I tried using the following declaration. Please correct me what's gone wrong here.
Since in my i/p file i have 3 student records with varying subjects( Minimum 1 subject and maximum is 6 subject) , i use the following array declaration. sTUDENT ID ( 2 CHARS) SUBJECT( 3CHARS)
I/p file layout :
01 STUDENT-REC.
02 STU-ID PIC 9(2).
02 SUB1 PIC X(3).
02 SUB2 PIC X(3).
02 SUB3 PIC X(3).
02 SUB4 PIC X(3).
02 SUB5 PIC X(3).
02 SUB6 PIC X(3).
I/p file data:
01AAA
02BBBDDDEEEHHHJJJPPP
03TTTUUUOOO
01 CNT PIC 9(1).
01 STUDENT-REC.
02 STUD-DETAILS OCCURS 5 TIMES INDEXED BY I1.
03 STUDNT-ID PIC 9(2).
03 SUBJECT OCCURS 1 TO 6 TIMES DEPENDING ON CNT.
05 STU-SUB PIC X(3).
Now to load the array from file i used the below logic.
Read input file
Move STU-ID to STUDNT-ID(I1).
move SUB1 to STU-SUB(I1,CNT).
Add 1 to CNT.
move SUB2 to STU-SUB(I1,CNT).
Add 1 to CNT.
likewise till SUB6 ....
then SET I1 up by 1 ....and repeat the above.
This loaded the array but i am unable to do a SEARCH in the array.
Please do let me know what's going wrong. |
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chavinash2004
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Joined: 30 Jun 2010
Posts: 37
Location: hyderabad
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Hi all,
Please any of yuou explain me what is the difference between IF and IF NOT with example. |
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dbzTHEdinosauer
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Joined: 20 Oct 2006
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chavinash2004,
If you start a new thread, as you should have,
you will receive an answer;
if not, you will not.
Ambili S,
| Quote: |
| This loaded the array |
no, that is untrue
there will only be one value of cnt - there is only one variable.
as a result, the value of count will dictate howmany classes there
are for each student.
based on your input, you will have 3 classes for each student.
you know by examining your input, that each student does not have the
same number of classes.
yet, by virtue of the way you decided to design the table,
you have no way to determine the actual number of classes each student has.
there are a variable number of students.
though each student can have between 1 and 6 classes, your design does not allow for anyway to determine howmany each student has.
suggest you go back an re-read (or read) the manual, specifically the programmers guide,
and learn about the restrictions of defining complex ODO's. |
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Ambili S
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Joined: 06 Sep 2007
Posts: 112
Location: India
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Sir is this declaration correct :
01 STUDENT-REC.
03 CNT PIC 9(1).
03 STUDENT-TABLE OCCURS 5 TIMES INDEXED BY I1.
05 STU-ID PIC X(02).
05 STU-SUB PIC X(03) OCCURS 1 TO 6 TIMES DEPENDING ON CNT
INDEXED BY I2.
07 STU-SUB PIC X(3).
If yes , then while loading the array how should the subjects be defined . Should it be :
MOVE SUB1 TO STU-SUB(I1,I2)
SET I2 UP BY 1
MOVE SUB2 TO STU-SUB(I1,I2) ...Likewise till SUB6
If it's this way then when should i increase the value of CNT ?
I read the complex ODO part in the guide . But couldn't understand how to load the complex ODO array and how to refer to the varying part in SEARCH . Could you please help me with it ? |
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dbzTHEdinosauer
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Ambili S,
as Kolusu says: **Sigh**
1. my suggestion of table definition is posted about 6 posts back.
2. your definition means that the number of classes that the last student has,
will determine how many classes every student has.
3. I will help you with your procedural code,
when I think you have decided on a table definition that I think will work.
Item 2. above explains why I don't think your current definition is acceptable.
HINT:
Each student can have a varying number of classes,
but within a definite range of 1 and 6.
so,
IF class(student-index,class-index) = spaces
Then student(student-index) does not have a class.
IF class(student-index,class-index) > spaces,
then student(student-index) has a class. |
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Ambili S
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Posts: 112
Location: India
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Yes , according to my data the Number of Students is fixed , but the classes for each will vary from 1 to 6. So how do i declare this array , load and then do a SEARCH in the array. This is my question. Hope now it's clear. According to your declaration :
| Quote: |
05 student-count pic s9(7) comp-3 value zero.
05 student-table occurs 0 to 5000 times depending on student-count indexed by student-idx.
10 student-id pic x(02).
10 class pic x(03) occurs 6 times indexed by class-idx.
88 no-class value spaces. |
student-id also varies along with class. But for mine student-id remains fixed i.e. 3 students but the classes opted by each of them varies form 1 to 6.
Please help me. |
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dbzTHEdinosauer
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Joined: 20 Oct 2006
Posts: 6966
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Ambili S,
The number of classes for each student is variable.
therefore if the class table defined for each student is to be an ODO,
then each student must have his/her own 'class-count'.
From the manual:
All data-names used in the OCCURS clause can be qualified; they cannot be subscripted or indexed
so, in order for your table definition to work,
you need the following modification:
| Code: |
01 CNT PIC S9(3) COMP-3.
01 STUDENT-TABLE.
02 STUD-DETAILS OCCURS 5 TIMES
INDEXED BY I1.
03 STUDNT-ID PIC 9(2).
03 STUDNT-CLASS-CNT PIC S9(3).
03 SUBJECT OCCURS 1 TO 6 TIMES
DEPENDING ON CNT
INDEXED BY I2.
05 STU-SUB PIC X(3).
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| Code: |
set i1 to 1
Read input file
Move STU-ID to STUDNT-ID(I1).
move SUB1 to STU-SUB(I1,1).
move SUB2 to STU-SUB(I1,2).
move SUB3 to STU-SUB(I1,3).
move SUB4 to STU-SUB(I1,4).
move SUB5 to STU-SUB(I1,5).
move SUB6 to STU-SUB(I1,6).
evaluate true
when sub2 = spaces
move 1 to cnt
when sub3 = spaces
move 2 to cnt
when sub4 = spaces
move 3 to cnt
when sub5 = spaces
move 4 to cnt
when sub6 = spaces
move 5 to cnt
when other
move 6 to cnt
end-evaluate
move cnt to STUDNT-CLASS-CNT(T1)
then SET I1 up by 1 ....and repeat the above.
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to refer to a student, you set I1 to appropriate value.
to refer to a student's class,
after setting I1,
you move STUDNT-CLASS-CNT(T1) to CNT
then you can refer to a class as STU-SUB(I1,I2)
until I2 > cnt |
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Ambili S
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Joined: 06 Sep 2007
Posts: 112
Location: India
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Thanks a ton for this. It really helped me to understand the varying array portion. One more question , here i wanted to display all those student id's who have opted for class say 'BBB' . Say the 1st , 3rd and 5th student opt for class BBB. So how can i do this , as i tried with search and it's not working.
Here's my i/p file :
01AAABBB
02CCCDDDEEEFFFNNNHHH
03IIIJJJBBBLLL
04OOOYYYWWWRRR
05IIIJJJBBBLLL |
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dbzTHEdinosauer
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Posts: 6966
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Using the following definition, (I like level 88's):
| Code: |
01 CNT PIC S9(3) COMP-3.
01 STUDENT-TABLE.
02 STUD-DETAILS OCCURS 5 TIMES
INDEXED BY I1.
03 STUDNT-ID PIC 9(2).
88 NO-STUDNT VALUE ZERO.
03 STUDNT-CLASS-CNT PIC S9(3).
03 SUBJECT OCCURS 1 TO 6 TIMES
DEPENDING ON CNT
INDEXED BY I2.
05 STU-SUB PIC X(3).
88 SUB-IS-BBB VALUE 'BBB'.
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before populating the table,
| Code: |
SET NO-STUDNT(1)
NO-STUDNT(2)
NO-STUDNT(3)
NO-STUDNT(4)
NO-STUDNT(5) TO TRUE |
now, to search the table,
because the true count of subjects is STUDNT-CLASS-CNT(I1)
and CNT is the odo object,
CNT must be populated before each search with STUDNT-CLASS-CNT(I1)
thus, to search for all students taking subject :BBB
| Code: |
PERFORM VARYING I1
FROM 1
BY 1
UNTIL NO-STUDNT(I1)
OR I1 > 5
MOVE STUDNT-CLASS-CNT(I1) TO CNT
SEARCH SUBJECT
WHEN SUB-IS-BBB(I1,I2)
DISPLAY STUDNT-ID(I1)
END-SEARCH
END-PERFORM
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