Execution of the jcl step but in RANDOM Order

jayant_tibhe · New User Joined: 25 Feb 2006 Posts: 27 Location: Pune

Hi Friends,
I have a doubt.

How do I use the RESTART parameter to execute a job with 10 steps, of which I need to execute step1 then execute step9, without executing the steps in-between .
Suppose i have 10 steps in my jcl STEP1, STEP2........STEP10 now i want to execute only STEP1, STEP5, STEP8, STEP9, STEP10. is there any chance to execute without COND parameter, we had IF cond but it makes the jcl some what complex

superk · Posted: Sat Feb 25, 2006 7:20 am

Please search first. This question has been asked many times before.

See this post.

pbgunasekar · New User Joined: 28 May 2005 Posts: 26 Location: Chennai

hi,
better you copy all the steps you need to execute in the other member and run.

KS · New User Joined: 28 Feb 2006 Posts: 91 Location: Chennai

Hi,

You can use Restart parameter if you need to start executing from certain steps and can bypass the needed steps using COND parameter.

Thanks,
KS

i413678 · Posted: Wed Mar 01, 2006 7:10 pm

Hi,

you can use DPRTY parameter for each and every step in which order you want to execute the steps.......

DPRTY=(val1,val2) the value will be calculated as
val1+val2*15

based on the value in ascending order the corresponding steps are executed....

correct me if I am wrong................

cheers.......................

pavan

martin9 · Posted: Thu Mar 02, 2006 2:57 pm

simply delete all the steps not needed and rerun the job.
if you want to control the job's flow with IF-ENDIF,
i don't see why it should be more complex as COND.
at least it is not the reverse wired logic of the COND,
which it makes more complex, more useful is IF-ENDIF,
because of it's positive condition phrase.
don't try harder...

martin9

tip: make it as simple as possible