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Manicka Yazhini T
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Joined: 01 Jun 2011
Posts: 7
Location: INDIA
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Hi! I have already looked into the posts regarding this topic. But still am not clear of how can we find the following values in calculating the record size for AIX
I need to know how can I find CI, CA and n in the following formula
RECORDSIZE = (RECSZ MAXLRECL) where
MAXLRECL = CI/CA * (CISZ - 10)
RECSZ = 5 + AIXKL + (n*BCKL)
Thanks,
MY |
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PeterHolland
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Joined: 27 Oct 2009
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Location: Netherlands, Amstelveen
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Robert Sample
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Location: Dubuque, Iowa, USA
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| Quote: |
| RECSZ = 5 + AIXKL + (n*BCKL) |
BCKL is Base Cluster Key Length -- the length of your primary key.
AIXKL is the length of the alternate index key.
n is the number of duplicates you can have for a single primary key (1 if duplicates are not allowed) |
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Manicka Yazhini T
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Joined: 01 Jun 2011
Posts: 7
Location: INDIA
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Thanks both. So now it looks like n come by either by knowing or by guessing.. Ok.
BASE: KEYS (48 0)
AIX : KEYS (4 32)
and both have CISZ (8192) and CYL (1 1))
I calculated my RECSZ as 5 + 4 + (2000 * 48) = 96009
Can I give RECORDSIZE (96009 96009) in AIX defiinition? |
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PeterHolland
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| yes |
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Manicka Yazhini T
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Joined: 01 Jun 2011
Posts: 7
Location: INDIA
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| Thats Great. In deed it worked in my test job, I just wanted to confirm from you experts so that I can have a reliable info. Thanks Again..!! |
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PeterHolland
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Location: Netherlands, Amstelveen
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Good,
but you could have tested first to see if it could be done. |
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Robert Sample
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Location: Dubuque, Iowa, USA
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| Record size for the alternate index definition can be anything up to the limit (n in the formula cannot exceed 32767). |
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