SQL Error Code -803

ranga_subham · New User Joined: 01 Jul 2005 Posts: 51

How to solve the -803 SQL return code by a COBOL DB2 program?

priyesh.agrawal · Posted: Fri Jul 01, 2005 3:36 pm

Basically its a violation of UNIQUE constraint.

Examine the definitions for UNIQUE INDEX in the INDEX SPACE 'indexspace name' to determine the uniqueness constraint imposed.
Please refer to SYSIBM.SYSINDEXES for the 'indexspace name' and the associated 'index name'. For an UPDATE statement, verify that the specified operation is consistent with the uniqueness constraint. If this does not indicate the error, examine the object table to determine the cause of the problem.
For an INSERT statement, examine the object table to determine which values violate the uniqueness constraint. If the INSERT statement contains a subquery, match the contents of the table addressed by the subquery and the contents of the object table to determine the cause of the problem.
For a DELETE statement, examine the index key columns in the table that defines the index. These columns contain a foreign key, which when set NULL on a cascade delete from the object table, causes the duplicate values.

Regards,

Priyesh.

jagadeshdvn · Posted: Thu Jul 07, 2005 10:57 pm

Just to add some more info on -803:

-803 AN INSERTED OR UPDATED VALUE IS INVALID BECAUSE THE INDEX IN INDEX
SPACE indexspace-name CONSTRAINS COLUMNS OF THE TABLE SO NO TWO
ROWS CAN CONTAIN DUPLICATE VALUES IN THOSE COLUMNS. RID OF EXISTING
ROW IS Xrid

Explanation: The table that is the object of the INSERT or UPDATE
operation is constrained (by UNIQUE INDEX in the INDEX SPACE
indexspace-name to have unique values in certain columns. Completion of
the requested INSERT or UPDATE would result in duplicate values occurring
in row rid.

If a view is the object of the INSERT or UPDATE statement, the table that
defines the view is constrained. The update might also be caused by a
DELETE operation of a parent row that cascades to a dependent row with a
delete rule of SET NULL.

System Action: The INSERT, UPDATE, or DELETE statement cannot be
executed. The object table is unchanged.

vibhor_chodha · New User Joined: 08 Jul 2005 Posts: 2

The SQL - 803 error occurs on the violation of a UNIQUE constraint.

The first thing then, that comes to mind is to examine the definitions for UNIQUE INDEX in the INDEX SPACE to determine the uniqueness constraint imposed.

Please refer to SYSIBM.SYSINDEXES for the indexspace. For an UPDATE statement, verify that the specified operation is consistent with the uniqueness constraint.

ranga_subham · New User Joined: 01 Jul 2005 Posts: 51

Thank you people.