I know that MHASH is free library which contains many hash algorithms to get hash code. In my current program 3 dynamic calls goes to MHASH to invoke SHA-1 hash algorithm.The requirement is to invoke SHA-256.i.e. currently the output is 24bit, but i should make changes to get 32bit. If anybody have come across such a scenario please enrich with some essential data. How to invoke SHA-256 hash algorithm which exists in MHASH library from COBOL?
If the query is not clear please let me know...
Joined: 06 Jun 2008 Posts: 8280 Location: Dubuque, Iowa, USA
You probably need to consult your MHASH documentation to find the answers; possibly post to the MHASH developers board?
The requirement is to invoke SHA-256.i.e. currently the output is 24bit, but i should make changes to get 32bit
I especially do not understand what you mean by this, since SHA-1 generates 160 output bits and SHA-256 generates 256 output bits; if you're cutting down the output to 24 bits then you're really messing up the algorithm. If you're referring to a 24-bit load module that needs to go to 31-bits (note that 32-bit load modules don't exist per se on z/OS systems, just 31-bits due to the architecture), then you're going to run into problems calling the 24-bit MHASH routine using addresses that MHASH cannot access.
if this is the case how does this thread relate to mainframe cobol...
the infrastucture of mhash is provided for C language programs
to invoke it from a mainframe non USS cobol looks not trivial
it implies quite bit of skills and a lot of work being done
if it has been done You might probably get more help from the people
who installed mhash in Your environment rather than from a public/generic cobol forum