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pauly_william
New User
Joined: 15 Oct 2007 Posts: 27 Location: Canada
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I'm trying to alter the boundaries of a loop using a compound variable (ie if condition is met move the end of an entry to another line). Hopefully the code illustrates better what I'm trying to accomplish:
Code: |
/* rexx */
enum = 1
entry.enum.start = 4
entry.enum.stop = 6
Do i = entry.enum.start to entry.enum.stop
Say "Ln# :"i
If i = 5 Then entry.enum.stop = 10
End i
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Output is:
Ln# :4
Ln# :5
Ln# :6
....instead of all the way to Ln# :10
So my question would be, is it possible to alter the loop inside when a condition is met or is the boundaries given will be the boundaries committed to? |
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expat
Global Moderator
Joined: 14 Mar 2007 Posts: 8797 Location: Welsh Wales
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Maybe a shift in logic, but be warned - This code is untested and is intended purely as a guide
Code: |
/* rexx */
eof = 0
enum = 1
entry.enum.start = 4
entry.enum.stop = 6
i = entry.enum.start
Do until(eof)
Say "Ln# :"i
If i = 5 Then entry.enum.stop = 10
if i = entry.enum.stop
then eof = 1
i = i + 1
End
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enrico-sorichetti
Superior Member
Joined: 14 Mar 2007 Posts: 10873 Location: italy
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the logic behind is a bit odd, but....
the answer is nooo
the do loop boundaries are computed at do loop initialization
( You can check by running with TRACE "I" )
the only whay ( I tested ) is with a while
Code: |
start = 4
end = 6
i = start
do while ( i <= end )
say "i " i
if i = 5 then end = 10
i = i + 1
end |
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