[Solved]How to calculate total no of Bytes

ragin · New User Joined: 20 Feb 2005 Posts: 16

Hi frndz,
I need the following o/p with calculation of how to calculate the total no of bytess in the following:
01 rec1 .
02 a pic x(6).
02 b redefines a.
03 c occurs 6 times pic 9.
02 d occurs 4 times.
03 e pic x(5).
03 f pic 999.

Answer:
a)38.
b)44
c)14
d)32

Now i need to know how to calculate total no of bytess in the above prog.i need it with calculation.kindly update me ASAP.

gorle_n4 · New User Joined: 11 Mar 2005 Posts: 8 Location: hyderabad

01 rec1 .
02 a pic x(6).
02 b redefines a.
03 c occurs 6 times pic 9.
02 d occurs 4 times.
03 e pic x(5).
03 f pic 999.

here b is a redefining a so same memory will be shared so there it is occupying only 6 bytes
c is a group element and d is an elementary item of c. (6+4=10)
e=5
f=3
6+10+5+3=24
so answer is 24
Answer:
a)38.
b)44
c)14
d)32

learnmf · Active User Joined: 14 Mar 2005 Posts: 123

rsshanmugam · New User Joined: 08 Mar 2005 Posts: 62 Location: Basildon

hai friend the answer is 38 here we go how it happened

01rec1 .
02 a pic x(6).
02 b redefines a.
03 c occurs 6 times pic 9.
02 d occurs 4 times.
03 e pic x(5).
03 f pic 999

6 + 4 * 5 + 4 * 3 = 44 . since b redefines a they share same space

satyanarayana.chitneni · New User Joined: 28 Mar 2005 Posts: 4 Location: hyderabad

Hi friends,

rsshanmugam is right .

satyanarayana.chitneni · New User Joined: 28 Mar 2005 Posts: 4 Location: hyderabad

Hi,

Let me know where the 'c' will be stored?

'b' redefines 'a' means both variables adress is same, additional space(additional elementary items of 'b') of 'b' will be appended to space of 'a'.

So i hope 44 is the right answer.

Please give me clear answer whether i am right or not.

Regards,
Satya

learnmf · Active User Joined: 14 Mar 2005 Posts: 123

maverick05 · New User Joined: 14 Apr 2005 Posts: 54 Location: Earth

Hi Satya,

You have mentioned 6 + 4 * 5 + 4 * 3 = 44 . But i think
6 + 4 * 5 + 4 * 3 = 38. Just check the calculation.Correct me i am wrong as i'm weak in maths

mmwife · Super Moderator Joined: 30 May 2003 Posts: 1592

HI Satya,

The 6 occurences of the 1 byte c occupy the same space as the 6 byte a.

BTW guys, to avoid confusion, it's best to use parens "()" when showing arith, e.g.:

6 + ( 4 * 5) + (4 * 3) = 38

or more closely describing the record layout:

(1)6 + ( 5 + 3)4 = 38 the numbers within the parens rpresent the
lengths of each elementary item; the numbers
outside the parens represent the occurs.

Chandukc · New User Joined: 25 Apr 2005 Posts: 2

Shanmugam is correct,but the equation he has given is wrong I think.Coorect me if I'm wrong.

ovreddy · Posted: Tue Apr 26, 2005 2:55 pm

Hi,

01 rec1 .
02 a pic x(6). (6 Bytes)+
02 b redefines a. (same memory so 0)+
03 c occurs 6 times pic 9. (same memory child so 0)+
02 d occurs 4 times. (4*8=32 total child length)+
03 e pic x(5). (5)
03 f pic 999. (3)

So 38 is the answer...

Tip: You can use Calculator to calculate the length.

Thanks,
Reddy.