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sobana
New User
Joined: 11 Nov 2006
Posts: 3
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HI
can anyone help me to subtract two dates using any function in cobol |
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William Thompson
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Joined: 18 Nov 2006
Posts: 3156
Location: Tucson AZ
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Enterprise COBOL for zOS Language Reference Version 3 Release 3 igy3lr20
Chapter 22. Intrinsic functions
INTEGER-OF-DATE
The INTEGER-OF-DATE function converts a date in the Gregorian calendar from standard date form (YYYYMMDD) to integer date form.
Number-of-Days = Integer-of-Date (YYYYMMDD)
- Integer-of-Date (YYYYMMDD) |
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priyesh.agrawal
Senior Member
Joined: 28 Mar 2005
Posts: 1448
Location: Chicago, IL
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Sobana,
As Mr. William already guided you on to right way, just few lights on the functioning.
INTEGER-OF-DATE function returns value as an integer that is the number of days that the input date succeeds December 31, 1600 in the Gregorian calendar. The function result is a seven-digit integer with a range from 1 to 3,067,671.
So basically INTEGER-OF-DATE(INPUTDATE) would return an integer representing number of days between 12/31/1600 and your input date.
So now you should not be having problem understanding how this works:-
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COMPUTE NUMBER-DAYS-1 = FUNCTION INTEGER-OF-DATE(YYYYMMDD). //*input date 1
COMPUTE NUMBER-DAYS-2 = FUNCTION INTEGER-OF-DATE(YYYYMMDD). //*input date 2
COMPUTE DIFFERENCE-DAY= NUMBER-DAYS-1 - NUMBER-DAYS-2. |
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