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Joe_Song
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when i define varinat as below;
DCL 1 INPUT_REC ,
2 FILLER15 CHAR(01),
2 SAP_ORDER_LINE FIXED BINARY(31) UNALIGNED;
By default the fixed binary is alighend, so anyone can tell me why the input_rect length is 5 when using unaligned attribute. If by default, what's the length? |
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PeD
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The length of fields never changed : FILLER15 is 1 and SAP_..... is 4.
When Aligned is used the starting position can change and the mapping can add extra bytes. If you really want to learn that, I can give you a reference.
Ah Good old days !!! |
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Joe_Song
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| Could you give me the reference for it? appreciate it. |
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Joe_Song
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in fact in my program , i though the record lenth is 5 so i write it to the output file which i define 5 length, but when i use the default aligned attribute to the SAP... field, the job run error at the record variant length is greater than the file length.
so it means the length changed ,right? or what happend in detail? |
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PeD
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PeD
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As said, when aligned, extra bytes can be added.
So if the length of every field is constant, the total length of the structure can be bigger.
Follow the rules  |
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Joe_Song
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| any way to know how much it's added? |
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PeD
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... follow the rules ... 
But you can also see that with :
- File Aid will tell you when you use the entry 8 if I remember well,
- your compiling list will tell you also.
- maybe FileManager ( don't know - possibly ).
- you can edit your file ans inspect the locations and count
- ..... |
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Robert Sample
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| The PL/I Language Reference (link at top of this page) section 8.5 on Data Alignment indicates in some cases doubleword alignment will be used, so as much as 7 bytes could be added. Specifics depend, though -- BINARY (31) is fullword aligned, so based on your layout 3 filler bytes would be added. |
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Joe_Song
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| sitll can find the right length. vey sad |
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PeD
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Robert,
Not sure. It is more complex.
Joe,
have a look here ( via File-Aid rules )
| Code: |
FIELD
--------- FIELD LEVEL/NAME ---------- -PICTURE- -NUMBER START END LENGTH
INPUT_REC 1 13 13
2 FILLER15 CHAR(1) 1 1 1 1
2 SAP_ORDER_LINE BFX(31) 2 2 5 4
2 FILLER15 CHAR(1) 3 6 6 1
2 SAP_ORDER_LINE BFX(31) 4 10 13 4
******************************* Bottom of data ********************************
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Joe_Song
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| yes, if we just sum every field , it's sure the length is the total of every field. but for the structure, the total length will change, it's not 38 . not sure where really take effect? |
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PeD
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???????? the sum of every field is ( in my exemple ) 10.
The length of the structure is ( not 38 ?? ) but 13.
And the data are stored accordingly by the program in the file.
It is a question of addressing. |
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Joe_Song
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| So it's not fixed for the length, right? everytime the total length should not same according to the system allocation. |
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PeD
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I am not sure I understang correctly.
But...
To keep consistancy in your data, you MUST keep the same structure applied on the file.
It must be a matching between the data in the file and the layout.
Cheers |
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dick scherrer
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Hello,
I don't "speak" pl/i, but is there not a compiler option that shows the displacement of each field from some "base".
Looking at these displacements, could one see what alignment caused to the data layout? |
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PeD
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That's what I said, Dick.
On the other hand, it can be a pure academic discussion.
If you use the fileds in a PL/I program, each field is written/read by its name. So no problem.
The problem - the difficulty - can happen when you read "manually-visually" data from a file with the help of a structure with aligned attribute.
Some times it is confusing. |
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