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Regarding the RDW of VB file.


IBM Mainframe Forums -> DFSORT/ICETOOL
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samuel_Inba

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Joined: 03 Jan 2008
Posts: 53
Location: Chennai

PostPosted: Thu Dec 18, 2008 12:33 pm
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Hi,
I was trying to read the RDW(1-4 bytes) of a VB file which has the record length of 311 .pls find the code below.

The first 2 bytes should have the record length+4 and 3 and 4th has zeros( correct me if i am wrong), I used the below mentioned code it displayed the actual record length, but when i tried to display all the 4 bytes it showed some incorrect numbers.

My Input file has lrecl 315 and FRMT is VB.

Code:

  OPTION COPY                                           
  OUTFIL VTOF,BUILD=(5,311,1,2,BI,SUB,+4,EDIT=(IIIIT))   


The above code displayed my desired result...

<data> <rec length>

but when i used,
Code:

  OPTION COPY                                           
  OUTFIL VTOF,BUILD=(5,311,1,4,BI,EDIT=(IIIIT))   


expected output: 1-2 bytes : recd length+4 and 3-4: zeros.


Please clarify.

Thanks,
Sam.
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enrico-sorichetti

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Joined: 14 Mar 2007
Posts: 10803
Location: italy

PostPosted: Thu Dec 18, 2008 12:43 pm
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the numbers might look strange but there is a logic

the rule for RDW is ...
1st halfword the record lenght
2nd halfword ..... binary zeroes

carry on a bit of math to find out the differences ,
for example for a record with a length of 80 bytes
You would have rdw=x'00500000'

and taking the first hafword You would get 80
taking erroneously the whole rdw You would get 5242880 ( handheld math )
maybe something diferent if he edit mask/picture is inadequate

the results is right , the process is wrong
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samuel_Inba

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Joined: 03 Jan 2008
Posts: 53
Location: Chennai

PostPosted: Thu Dec 18, 2008 12:59 pm
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Thanks a lot for your quick reply. That did throw light on the result i got.
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