Initiate a JCL ?

Rameshs · Posted: Thu Mar 09, 2006 12:26 pm

A job can maximum of 255 steps. So if we want to execute more than 255 steps.

can we able to trigger a jcl from another jcl ?

ofer71 · Posted: Thu Mar 09, 2006 12:40 pm

Sure, you've got few methods:
1 - Use batch TSO (IKJEFT01) with the SUBMIT command.
2 - Call REXX from a job to submit other jobs.
3 - Use other programming language to submit job from a job (like COBOL, NATURAL, Assembler etc.).
4 - Make your last step an IEBGENER that its input will be the next job, and the output is allocated to INTRDR.

O.

KS · New User Joined: 28 Feb 2006 Posts: 91 Location: Chennai

Hi,

Already discussed in the forum.
To execute more than 255 steps : We need to split jcl into two jcls , at the end of the first jcl check the condition code and if successful you can initiate the second jcl.

Thanks,
KS

KS · New User Joined: 28 Feb 2006 Posts: 91 Location: Chennai

Make your last step an IEBGENER that its input will be the next job, and the output is allocated to INTRDR?

Check for the condition code of the last step in JCL.
IF RC = O THEN do the following .

//STEP050 EXEC PGM=IEBGENER
//SYSPRINT DD SYSOUT=*
//SYSUT1 DD DSN=SYSPDA.JCLLIB(JCL2),DISP=SHR
//SYSUT2 DD SYSOUT=(A,INTRDR)
//SYSIN DD DUMMY

Here SYSPDA.JCLLIB is the dataset where ur second JCL resides.
INTRDR is a special SYSOUT data set that other programs can use to submit jobs, control statements.

ofer71 · Posted: Thu Mar 09, 2006 4:36 pm

INTRDR is a program, not dataset ...

O.

KS · New User Joined: 28 Feb 2006 Posts: 91 Location: Chennai

I agree its not a dataset..but its not a proper program like cobol too.
Its neither a dataset nor a program.
Kindly verify by putting Quick watch (qw INTRDR) in ISPF.Its mentioned as a dataset.

Thanks,
KS

superk · Posted: Thu Mar 09, 2006 5:44 pm

In many of the IBM manuals, they also refer to sysout as being a dataset, so I guess calling it that is correct. Confusing, maybe.

Rameshs · Posted: Wed Mar 15, 2006 6:21 pm

All methods r working fine.

Thanks kuttisatha and superk for your valuable informations.

How to submit the job from cobol program ?.

Thanks,
Ramesh

superk · Posted: Wed Mar 15, 2006 6:53 pm

See the above post from KuttiSatha. Use the same method.

Rameshs · Posted: Wed Mar 15, 2006 7:05 pm

Here is the link

To submit JCL via a Cobol program?

http://ibmmainframes.com/viewtopic.php?t=4102&highlight=trigger+job

Thanks,
Ramesh

martin9 · Posted: Thu Mar 16, 2006 6:21 pm

hy Rameshs,

you really have such a job,
or you just want to try out the limits of jes?
a job with 255 steps is simply not maintainable,
therefore my tip: don't do it!

while using this you might get other limitation problems...

martin9