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sivakanuri

New User

Joined: 07 Jun 2004
Posts: 5

 Posted: Mon Jun 14, 2004 11:32 pm    Post subject: COBOL Interview Program Enquiry Study the following 01 A PIC 99V0 VALUE 5 01 B PIC 9V9 VALUE 6 01 C PIC 99V9 VALUE 2.5 01 D PIC 99 VALUE 3 COMPUTE A ROUNDED B C = A+B*C/D ON SIZE ERROR PERFORM PRINT-ERROR the comments of A.B.C after execution of the above statement are a.A=10 B=0 C=10 b.A=10 B=9.9 C=9.9 c.A=10 B=0 C=9.9 d.A=10 B=6 C=10 plz study the code an give the valid option , and also explain hou u got the answer,urgent plz. thanks in advance

mcmillan

Joined: 18 May 2003
Posts: 1203
Location: India

Posted: Fri Jun 18, 2004 8:07 am    Post subject: Re

The answer is d) A = 10, B = 6, C = 10

You can not initialize a non-numeric (99v0) item with 5, so I assume as:

 Quote: 01 A PIC 99V9 VALUE 5 01 B PIC 9V9 VALUE 6 01 C PIC 99V9 VALUE 2.5 01 D PIC 99 VALUE 3

Now the size of A is 3 Bytes (V doesn't occupy any memory)

B - 2 Bytes

C - 3 Bytes

 Quote: COMPUTE A ROUNDED B C = A+B*C/D

As by the rule,

B * C = 15.0 (It's not 15)

(B * C ) / D = 5.0

A + (( B * C) / D) = 10.0

A = 10.0

B = 0.0 (has only 2 Bytes, so value truncated)

C = 10.0

But yu have specified ON SIZE ERROR...

 Quote: ON SIZE ERROR PERFORM PRINT-ERROR

If on size error specified, then insted of truncation, the value will be restored.

That's instead of 0.0 the value of B getting restored as 6.0 (as per in VALUE clause)

A = 100 (10.0 - assumed decimal)

B = 60 (6.0)

C = 100 ( 10.0)
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