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abend sort based on count records in group

 
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anatol

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Joined: 20 May 2010
Posts: 101
Location: canada

PostPosted: Mon Oct 17, 2016 10:10 pm    Post subject: abend sort based on count records in group
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Hi,

I have file ( need just idea, so let it FB=80):

Code:

111111
111111
111111
111111
111111
111111
111111
111111
111111
111111
222222
222222
222222
222222
222222
222222


group is in position 1-6.
Is it possible to abend sort if records in any group is more than 7 ... Based on the file in example - abend, because group 111111 have more than 7 records
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Rohit Umarjikar

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Joined: 21 Sep 2010
Posts: 1640
Location: NY,USA

PostPosted: Mon Oct 17, 2016 10:28 pm    Post subject:
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Hint-
http://www.ibmmainframeforum.com/dfsort-icetool-icegener/topic5837.html
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anatol

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Joined: 20 May 2010
Posts: 101
Location: canada

PostPosted: Mon Oct 17, 2016 11:21 pm    Post subject: Reply to: abend sort based on count records in group
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Thank you ... I will try to check if I can use NULLOFL for my task... kind of doubt
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Bill Woodger

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Joined: 09 Mar 2011
Posts: 7279

PostPosted: Tue Oct 18, 2016 12:20 am    Post subject: Reply to: abend sort based on count records in group
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Well, you can very easily get an RC=4 if there are no groups with more than seven records (or any arbitrary known value). Have a subsequent step which abends when you get RC=0 in the step. Or deal with the RC=4 as good RC=0 as bad in your JCL, or your Scheduler.

Here's an OVERLAY. Put this under an IFTHEN=(WHEN=(logicalexpression) for your required condition,

Code:
OVERLAY=(5:Z,5:1,1,PD,ADD,+1,TO=PD,LENGTH=1)


If you desperately, desperately want a fake abend, that should do it.
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anatol

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Posts: 101
Location: canada

PostPosted: Tue Oct 18, 2016 12:29 am    Post subject: Reply to: abend sort based on count records in group
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Thank you, Bill .. I think it is better to work with RC, than force to abend . So include to output only records with more than 7 in group and RC=4 if output is empty, right?
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Bill Woodger

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Posts: 7279

PostPosted: Tue Oct 18, 2016 2:08 am    Post subject: Reply to: abend sort based on count records in group
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Yes.
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