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iknow
Active User
Joined: 22 Aug 2005
Posts: 411
Location: Colarado, US
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Hi All
I have a employee table with a salary field. How to calculate the second maximum salary in the employee table. Please provide the query. |
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sridevi2005
New User
Joined: 15 Sep 2005
Posts: 42
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Hi,
Try the following query.
Select min(salary) from employee
where salary > select salary from employee
where salary > avg(sal).
Please let me know if u have any query.
Thanks,
Sridevi |
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mathiprakash
New User
Joined: 29 Apr 2005
Posts: 14
Location: Pune, India.
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radhakrishnan82
Active User
Joined: 31 Mar 2005
Posts: 435
Location: chennai, India
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try this code:
| Code: |
SELECT DISTINCT (SALARY)
FROM EMPTABLE A
WHERE 2 =
(SELECT COUNT (DISTINCT (B.SALARY))
FROM EMPTABLE B
WHERE A.SALARY <= B.SALARY); |
Try the following to find the 'n'th max salary of the table:
Quote:
| Code: |
SELECT EMPSAL FROM EMPTABLE X
WHERE (n-1) IN
(SELECT COUNT(*) FROM EMPTABLE Y
WHERE X.EMPSAL > Y.EMPSAL) |
Hope this helps. |
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Kotes
New User
Joined: 03 May 2005
Posts: 5
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Hi Iknow,
What radhakrishnan wrote is sucessfully works. |
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jeyakanthan
New User
Joined: 18 May 2005
Posts: 12
Location: chennai
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this is simple query
select max(salary) from emp-table where salary NOT IN
(select max(salary) from emp-table) |
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nijugopalan
New User
Joined: 15 Oct 2005
Posts: 15
Location: pune
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select max sal from emp where sal<(select max sal from emp)
is this correct |
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