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Pick email Ids from a report.
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abhit007

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PostPosted: Wed Mar 07, 2012 12:03 pm
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Hi Guys,

I am facing a problem here. I want to write a REXX program to pick up all the email Ids present in a report. for example.

XYZ.ABC.DEF.GIH (PS)
**************************************************************
THIS REPORT IS USED TO FIND OUT THE NEW EMAIL IDS
INTRODUCED
**************************************************************
%EMAIL (ABC@GMAIL.COM,ABC.XYZ@GMAIL.COM ) -
%EMAIL (SUPPORT@GMAIL.COM CARDSSD@GMAIL.COM) -
%EMAIL (REPORT@GMAIL.COM ) -
%EMAIL (SUPPORT@GMAIL.COM ) -
%EMAIL (XXXXXXXXXXX@GMAIL.COM ) -
%EMAIL (SUPPORT@GMAIL.COM ) -
%EMAIL (BONUS@GMAIL.COM, PRODUCTS@YAHOO.CO.IN) -

From the above report I want to pick out all the email ids and write in other pds as:
ABC@GMAIL.COM
ABC.XYZ@GMAIL.COM
SUPPORT@GMAIL.COM
CARDSSD@GMAIL.COM
REPORT@GMAIL.COM
SUPPORT@GMAIL.COM
XXXXXXXXXXX@GMAIL.COM
SUPPORT@GMAIL.COM
BONUS@GMAIL.COM
PRODUCTS@YAHOO.CO.IN

Any idea??

Thanks,
Abhishek
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enrico-sorichetti

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PostPosted: Wed Mar 07, 2012 12:26 pm
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where are You stuck ....
in the logic or the code ?
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abhit007

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PostPosted: Wed Mar 07, 2012 1:03 pm
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To start with I am struck at the logic itself. :P
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dbzTHEdinosauer

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PostPosted: Wed Mar 07, 2012 1:10 pm
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1.
access a record
isolate and store email-address(es)
more records? goto 1
ouput all stored email-addresses

what would your logic in cobol be?

why did you pick REXX for this project?

how many lines in the report?
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Bill Woodger

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PostPosted: Wed Mar 07, 2012 1:11 pm
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Identify the lines from first word, or by location, being %e-mail.

Get rid of first word, opening and closing brackets, commas.

Take each remaining word and treat as an e-mail address.
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prino

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PostPosted: Wed Mar 07, 2012 2:06 pm
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Translate everything not alphanumerical, '@' and '.' to space, and use the REXX "word" and "words" functions. Any "word" containing an '@' sign is (probably) an email address.
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enrico-sorichetti

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PostPosted: Wed Mar 07, 2012 2:32 pm
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faster to write/test post the code that trying to explain


Code:
#!/usr/bin/rexx

list.1 = "%EMAIL (ABC@GMAIL.COM,ABC.XYZ@GMAIL.COM ) "
list.2 = "%EMAIL (SUPPORT@GMAIL.COM CARDSSD@GMAIL.COM) "
list.3 = "%EMAIL (REPORT@GMAIL.COM ) "
list.4 = "%EMAIL (SUPPORT@GMAIL.COM ) "
list.5 = "%EMAIL (XXXXXXXXXXX@GMAIL.COM ) "
list.5 = "%EMAIL (SUPPORT@GMAIL.COM ) "
list.6 = "%EMAIL (BONUS@GMAIL.COM, PRODUCTS@YAHOO.CO.IN) "
list.0 = 6

addr.0 = 0
do  i = 1 to list.0
    buff = list.i
    if  left(buff,6) = "%EMAIL" then do
        /* check for a properly delimited list */
        if  (pos("(",buff)) = 0 | ,
            (pos(")",buff)) = 0 then do
            say " bad EMAIL record" right(i,2) buff
            iterate
        end
        parse var buff with ."(" list ")" .
        /* provide both for comma/wsp delimited addresses */
        list = translate(list," ",",")
        do  j = 1 to words(list)
            a = addr.0 + 1
            addr.a = strip(word(list,j))
            addr.0 = a
        end
    end
end
do  a = 1 to addr.0
    say a addr.a
end


if the input format changes, do a bit of work Yourself
for example You might need to build from multi card list
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abhit007

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PostPosted: Wed Mar 07, 2012 3:57 pm
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Hi Enrico,

The code you have provided is working perfectly after a little tweaking.

I am reading the report from my dataset into a stem and then running the piece of code you have given to filter out the mail addresses. Comma and spaces were the only delimiters.
Since %EMAIL is not the only thing at the first place in a line, so I have removed the first para of your code. However, there are still some minor glitches as it is taking special characters like '-' and writing it in a new line.

Hi All,

Thanks for your help as well.



Many thanks for all the help.
Abhishek
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enrico-sorichetti

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PostPosted: Wed Mar 07, 2012 8:24 pm
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post an example of where MY the code fails,
my snippet as posted will parse correctly ANY list within parentheses
and build the single appearances correctly unless it contains commas or spaces
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don.leahy

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PostPosted: Wed Mar 07, 2012 9:45 pm
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Enrico, re your code sample: on my display, the lowercase "l" and the numeral "1" appear identical in the code window.

ie the line "do l = 1 to list.0" looks like "do l = l to list.0" icon_smile.gif
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Bill Woodger

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PostPosted: Wed Mar 07, 2012 10:12 pm
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1l1l1l1l1l1l1l1l1l1
Code:
1l1l1l1l1l1l1l1l1l1


1l1l1l1l1l1l1l1l1l1

It is not just enrico's stuff, it seems. How many years has it taken for anyone to spot that (well done Don!)? When you copy/paste from the coded stuff, you get the right ones, as above (first typed, copy/paste, coded, preview, copy/paste from Coded stuff on Preview).

Or is this a recent change? How could we tell :-)

EDIT: This is with Firefox, anyway.
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enrico-sorichetti

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PostPosted: Wed Mar 07, 2012 10:19 pm
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Quote:
Enrico, re your code sample: on my display, the lowercase "l" and the numeral "1" appear identical in the code window.

that' a common problem with some fonts

my code sample worked well AS CODED

just as a courtesy to Your eyes I edited the code to use j for the inner loop and i for the outer
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dbzTHEdinosauer

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PostPosted: Wed Mar 07, 2012 10:52 pm
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i personally never use the single alpha i, l, or o as a variable
since people tend to see what they want
instead of what is there.
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abhit007

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PostPosted: Thu Mar 08, 2012 1:00 am
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Hi Enrico,

Your code is working perfectly. I just had to alter it to suit my needs.

Hi All,

Next part of the problem:

Now I have to take each of these Ids from one dataset and search in my database (another dataset) for existence. If any of the address is not present then write in another file.

This database is again not a formatted one, having email Ids randomly, so we might have to use POS or something like that.

Can you please help?

Thanks,
Abhishek
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Pedro

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PostPosted: Thu Mar 08, 2012 10:44 pm
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Quote:
This database is again not a formatted one, having email Ids randomly, so we might have to use POS or something like that.


1. Change all '(', ')', and ',' to blanks.
2. for each word of each line, use POS function to see if it has the '@' character.
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abhit007

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PostPosted: Fri Mar 09, 2012 11:10 am
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enrico-sorichetti wrote:
post an example of where MY the code fails,
my snippet as posted will parse correctly ANY list within parentheses
and build the single appearances correctly unless it contains commas or spaces


Hi Enrico,

There is one problem. There are certain instances where parenthesis are not there. For example

%YMAIL (XYZVITY@GMAIL.COM,XG.RPCZPYRATIZNX@GMAIL.COM, -
CZYRYL.CZIAM@GMAIL.COM,XYNGCZAI.CZAN@GMAIL.COM, -
(DZZZA.AZMAD@GMAIL.COM,MARIYTTA.BZZCZRRYJADZ@GMAIL.COM, -
DYVAXXY.ATTZKARYN@GMAIL.COM,ALKA.JZA@GMAIL.COM, -
AAAT.XINGZ3@GMAIL.COM,VIXZAL.ZJZA@GMAIL.COM) -
FRZM (XYZVITY@GMAIL.COM) -

How this can be parsed?

Thanks,
Abhishek.
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enrico-sorichetti

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PostPosted: Fri Mar 09, 2012 11:36 am
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I made a note about ....
Quote:
for example You might need to build from multi card list

implied some kind of continuation ...

but You must set some rules ...

a string concatenation/sequence from a parsing point of view is an expression
and in any language in an expression the parentheses must be balanced

the example You posted is NOT parsable because the open and close parentheses are not balanced

You cannot blame on the parsing if Your input is wrong!
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enrico-sorichetti

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PostPosted: Fri Mar 09, 2012 11:40 am
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here is a snippet that will parse a properly parenthesized string

Code:


#!/usr/bin/rexx

list.1 = "%EMAIL (ABC@GMAIL.COM,ABC.XYZ@GMAIL.COM ) "
list.2 = "%EMAIL (SUPPORT@GMAIL.COM CARDSSD@GMAIL.COM -"
list.3 = "REPORT@GMAIL.COM - "
list.4 = "SUPPORT@GMAIL.COM ) "
list.5 = "%EMAIL (XXXXX_XXX.XXX@somefuckng-strange.address.COM ) "
list.6 = "%EMAIL (SUPPORT@GMAIL.COM ) "
list.7 = "%EMAIL (BONUS@GMAIL.COM, PRODUCTS@YAHOO.CO.IN) "
list.0 = 7

addr.0 = 0
indx = 1
buff = ""
do while ( indx <= list.0 )

    buff = strip(list.indx)
    say indx "*1 " buff
    indx = indx + 1
    do  while ( right(buff,1) = "-" & indx <= list.0 )
        buff = strip(buff,,"-") strip(list.indx)
        say indx "*2 " buff
        indx = indx + 1
    end
    /* do some checking for a wrongful continuation on last card */
    say indx "*3 " buff
    if  left(buff,6) = "%EMAIL" then do
        /* check for a properly delimited list */
        if  (pos("(",buff)) = 0 | ,
            (pos(")",buff)) = 0 then do
            say "bad EMAIL record" right(indx,2) buff
            iterate
        end
        parse var buff with ."(" list ")" .
        /* provide both for comma/wsp delimited addresses */
        list = translate(list," ",",")
        do  i = 1 to words(list)
            a = addr.0 + 1
            addr.a = strip(word(list,i))
            addr.0 = a
        end
    end
end
do  a = 1 to addr.0
    say a addr.a
end


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abhit007

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PostPosted: Fri Mar 09, 2012 11:42 am
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Quote:

the example You posted is NOT parsable because the open and close parentheses are not balanced


Hi Enrico,

%EMAIL (XYZVITY@GMAIL.COM,XG.RPCZPYRATIZNX@GMAIL.COM, -
CZYRYL.CZIAM@GMAIL.COM,XYNGCZAI.CZAN@GMAIL.COM, -
DZZZA.AZMAD@GMAIL.COM,MARIYTTA.BZZCZRRYJADZ@GMAIL.COM, -
DYVAXXY.ATTZKARYN@GMAIL.COM,ALKA.JZA@GMAIL.COM, -
AAAT.XINGZ3@GMAIL.COM,VIXZAL.ZJZA@GMAIL.COM) -
FRZM (XYZVITY@GMAIL.COM) -

Ignore the example in prev post , consider this example where parenthesis is balanced.
Since there are multiple Ids it is coming in multiple lines.

Thanks
Abhishek
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enrico-sorichetti

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PostPosted: Fri Mar 09, 2012 11:44 am
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and what about the
Quote:
FRZM (XYZVITY@GMAIL.COM)
?
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Anuj Dhawan

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PostPosted: Fri Mar 09, 2012 6:09 pm
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abhit007 wrote:
Ignore the example in prev post , consider this example where parenthesis is balanced.
Since there are multiple Ids it is coming in multiple lines.
Enrico, Working on a distant-contract, by any chance? icon_smile.gif
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Pedro

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PostPosted: Fri Mar 09, 2012 8:18 pm
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I think this is more simpler logic:
Quote:
1. Change all '(', ')', and ',' to blanks.
2. for each word of each line, use POS function to see if it has the '@' character.
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enrico-sorichetti

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PostPosted: Sat Mar 10, 2012 1:41 am
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Quote:
Enrico, Working on a distant-contract, by any chance?


nope!
writing scanners and parsers is one of my preferred subjects

so when I see something related I like to explore all the alternatives, not only just working ,
but also not trivial from a scanning/parsing algorithmic point of view

stay tuned I hav a nice snippet coming !
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