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SQL Code -305 in Join

 
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Suhaas

New User


Joined: 16 Apr 2009
Posts: 1
Location: Pune

PostPosted: Thu Nov 10, 2011 2:26 pm    Post subject: SQL Code -305 in Join
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I have below query in cursor...

SELECT A.A1
,A.A2
,B.B1
,B.B2
FROM
(SELECT X.A1
,Y.A2
FROM TABLE1 X
,TABLE2 Y
WHERE X.A3=Y.A4)
AS A
LEFT OUTER JOIN
TABLE3 B
ON B.B2=A.A2

Here A1, A2 and B2 are NULLable columns and B1 in NOT NULL

Resultant Data Set
A1 A2 B1 B2
1 2 1 2
2 10 5 10
3 12 -- --
7 11 -- --

However due to left outer join...For non matching rows from left side table i.e. TABLE1 and TABLE2, its making values of B1 and B2 as NULL (Though B1 is defined as NOT NULL)

While fetching its giving me -305 for column B1

I tried applying NULL indicator to column B1...Gave me Sql Code -303...Incomparable data items.

Please help...
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Bill Woodger

DFSORT Moderator


Joined: 09 Mar 2011
Posts: 7306

PostPosted: Thu Nov 10, 2011 2:34 pm    Post subject: Reply to: SQL Code -305 in Join
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This question is already posted in the Beginners forum. Where, quite frankly, your responses to suggestions cross way over the borders of rudeness.

It is no one else's code but yours, or your site's, that is not working. You have not been able to work out how, so maybe first you spend a further day followig your own advice?
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gylbharat

Active Member


Joined: 31 Jul 2009
Posts: 565
Location: Bangalore

PostPosted: Thu Nov 10, 2011 2:58 pm    Post subject:
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-305 THE NULL VALUE CANNOT BE ASSIGNED TO OUTPUT HOST VARIABLE NUMBER
position-number BECAUSE NO INDICATOR VARIABLE IS SPECIFIED
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enrico-sorichetti

Global Moderator


Joined: 14 Mar 2007
Posts: 10231
Location: italy

PostPosted: Thu Nov 10, 2011 3:10 pm    Post subject: Reply to: SQL Code -305 in Join
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do not double post.
people providing help on both forums are pretty much the same,
asking twice will not provide You with better help!
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