View previous topic :: View next topic
|
Author |
Message |
sobankumar ilango
New User
Joined: 05 May 2011 Posts: 3 Location: canada
|
|
|
|
deduction amount = 558.71
there are two children CS1 and CS2 both of them are expected to get CS1=279.35 and CS2=279.36
during calculation am using ( compute) values are getting rounded off to 279.36 and 279.36
ie it is actually exceeding the deduction amount
279.36+279.36=558.72 |
|
Back to top |
|
|
enrico-sorichetti
Superior Member
Joined: 14 Mar 2007 Posts: 10873 Location: italy
|
|
|
|
in general for rounding issues for financial/IR processes
ask Your organization to inquire at the IR offices about the standard/approved ways of carrying on the computations
in Italy for example the computations must be carried on with 4 decimal digits and displayed with two
let' s not quarrel that sometimes there might be differences,
but in my numbers(apple equivalent of excel ) worksheet after I made the changes everything has been checking out properly for qite a few years.
the best way is to ask the powers that be !
anyway for the particular case You are out of luck
dividing by two and rounding even with the proper rules it will alway result in an arithmetic mismatch |
|
Back to top |
|
|
Bill Woodger
Moderator Emeritus
Joined: 09 Mar 2011 Posts: 7309 Location: Inside the Matrix
|
|
|
|
sobankumar ilango wrote: |
deduction amount = 558.71
there are two children CS1 and CS2 both of them are expected to get CS1=279.35 and CS2=279.36
during calculation am using ( compute) values are getting rounded off to 279.36 and 279.36
ie it is actually exceeding the deduction amount
279.36+279.36=558.72 |
To get your specific result, where the remainder is allocated to a specific place, don't use ROUNDED.
You can use DIVIDE x BY y GIVING z REMAINDER a (sorry, bad planning).
Then add the "a" to the required field.
If you want to do it with COMPUTE, don't do the rounding, let it truncate, then subtract everything from the original amount and put whatever is left after this into your specific place. |
|
Back to top |
|
|
sobankumar ilango
New User
Joined: 05 May 2011 Posts: 3 Location: canada
|
|
|
|
thanks for the reply..I think I should make myself more clear..
the program selects the dependents(children in this case)
in a pro ration manner IE one by one and processes until the dependents are zero.( dependents are not always two).
I cannot get rid of round up option ( also it wont help)..
is there a solution for this problem ?
someone plzzzzzzzz help me !!!!!! |
|
Back to top |
|
|
GuyC
Senior Member
Joined: 11 Aug 2009 Posts: 1281 Location: Belgium
|
|
|
|
two algorythms :
1 ) give the last one , what ever is left.
suppose deduction = 20 ; dependents = 3
1st : 20. / 3 = 6.67
2nd: 20. / 3 = 6.67
3th: 20 - 6.67 - 6.67 = 6.66
2) remember leftovers.
1st: 20 / 3 = 6.67 => left = 13.33 / 2
2nd: 13.33 / 2 = 6.67 => left = 6.66 / 1
3th: 6.66 / 1 = 6.66 |
|
Back to top |
|
|
Bill Woodger
Moderator Emeritus
Joined: 09 Mar 2011 Posts: 7309 Location: Inside the Matrix
|
|
|
|
It doesn't matter how many you divide by, what matters is you know where the "balancing" part is to go.
Why do you think you can't get rid of the rounding? If you have to keep it, you have to work "upside down", in that you have to subtract your balancing item, and the specific place you want it to go will be less than all the others, not greater.
Divide Money-amount by Number-of-dependents giving Amounts-which-are-equal-per-dependent remainder Balancing-amount-which-is-not-equally-divisible (might be zero at times, won't ever be very big).
Each dependent gets Amounts-which-are-equal-per-dependent and one (your choice which) gets Amounts-which-are-equal-per-dependent plus Balancing-amount-which-is-not-equally-divisible.
Try it out, at least, then tell me your problems with the result. |
|
Back to top |
|
|
sobankumar ilango
New User
Joined: 05 May 2011 Posts: 3 Location: canada
|
|
|
|
hi BILL I owe u big thanks ... the logic given by you is working ...
thanks everyone ... thanks for the time |
|
Back to top |
|
|
|