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seman18
New User
Joined: 08 Feb 2009
Posts: 67
Location: hz
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I tried to store binary number into char, it shows 63 in hex
| Code: |
DCL BIN_E FIXED BIN(7) INIT(99);
DCL P5_E CHAR(1) BASED(ADDR(BIN_E)); |
however, when I change the below, it shows 00 in hex, why it failed? I am confused.
| Code: |
DCL BIN_E FIXED BIN(8) INIT(99);
DCL P5_E CHAR(1) BASED(ADDR(BIN_E)); |
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Akatsukami
Global Moderator
Joined: 03 Oct 2009
Posts: 1788
Location: Bloomington, IL
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| A FIXED BIN (7) can occupy one byte; a FIXED BIN (8) must occupy two (SIGNED is implied). P5_E is defined on the first byte of BIN_E. In your first example, the internal representation of 99 is 63; in the second, it's 0063...and P5_E is defined on the 00, which you are seeing. |
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