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Anurag Singh
New User
Joined: 20 Jan 2008
Posts: 25
Location: India
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PDS member which have the cobol code to compiled is :
ABC.JAN2010(XXX)
And in Code's Identification Division the Program ID is : YYY
Now the code is compiled , what will be the load library member for this program, whether it would be XXX or YYY and why ? |
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enrico-sorichetti
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Joined: 14 Mar 2007
Posts: 10873
Location: italy
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| the load module name will be the name assigned by the parameter specified in the linkage editor step |
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Robert Sample
Global Moderator
Joined: 06 Jun 2008
Posts: 8696
Location: Dubuque, Iowa, USA
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| Quote: |
| what will be the load library member for this program, whether it would be XXX or YYY and why ? |
The answer is ... it depends. If your linkage editor (binder) includes input statements like
| Code: |
ENTRY YYY
NAME ZZZ(R) |
then the load module name could be ZZZ. If your linkage editor (binder) SYSLMOD includes a member name, that will be the name in load library. The source PDS (or whatever) name is irrelevant -- so XXX will not be the name unless you code the linkage editor (binder) to call it that. Absent all other changes, YYY will be the name -- but only if you're not overriding it along the way. |
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MBabu
Active User
Joined: 03 Aug 2008
Posts: 400
Location: Mumbai
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not to mention that the source may be for a called routine that is not the main entry point so the source would have nothing to do with the final name.
So the answer to your question is... there is no answer given the information you supplied |
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