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lkhiger
New User
Joined: 28 Oct 2005 Posts: 89




Definite Integral interval [a, b]: Sf(x)dx = G(b)  G(a) where G'(x) = f(x) , or differential of G(x) = f(x).
Integrals appear in many practical situations.
Consider a swimming pool. If it is rectangular, then from its length, width, and depth we can easily determine the volume of water it can contain (to fill it), the area of its surface (to cover it), and the length of its edge (to rope it).
But if it is oval with a rounded bottom, all of these quantities call for integrals. Practical approximations may suffice for such trivial examples, but precision engineering (of any discipline) requires exact and rigorous values for these elements.
I create the query which calculate integral of 3 * X^2  2 * X in interval [2, 4]....
S(3 * X^2  2 * X)dx = X^3  X^2 and exact value of integral will be
S = (4^3  4^2)  (2^3  2^2) = 48  4 = 44.
We know nothing in our solution about exact value and differential and suppose to calculate approximate value of integral.
Process will stop when the absolute difference between current value of integral and previous become less or equal some eps real number.
Code: 
With
Source (Xstart, Xfinish, imgFunc, eps) as
(select double(2), double(4), '3 * X^2  2 * X', double(1.e3)
from sysibm.sysdummy1
)
,
Integral_calc (Xs, Xf, Xc, step, curint, prevint, eps, iterno) as
(select Xstart, Xfinish, double(Xstart  (Xfinish  Xstart) / 10.) Xc,
double((Xfinish  Xstart) / 10.) step, double(0), double(0), eps, int(0)
from Source
union All
select Xs, Xf, Xc + step, step, curint + Fc * step, prevint, eps, iterno + 1
from Integral_calc, table
(select 3 * power(Xc + step, 2)  2 * (Xc + step) Fc
from sysibm.sysdummy1 ) it
where Xc + step <= Xf
Union All
select Xs, Xf, Xs  (step / 2.), step / 2., 0., curint, eps, iterno + 1
from Integral_calc
where Xc + step > Xf
and abs(curint  prevint) > eps
)
,
Integral(integral_value, integral_image) as
(select curint, 'interval: ['  varchar(Xs)  ', '  varchar(Xf)  ']: S'  '('
 imgFunc  ')dx = '  varchar(round(curint, 3))
from Integral_calc, Source
where iterno = (select max(iterno) from Integral_calc)
)
select integral_value, integral_image from Integral 
Result of calculation:
Quote: 
INTEGRAL_VALUE............................ INTEGRAL_IMAGE
4.40005859378289E+001............... interval: [2.0E0, 4.0E0]: S(3 * X^2  2 * X)dx = 4.4001E1 
Could be very useful for students and engineers.
Lenny 

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lkhiger
New User
Joined: 28 Oct 2005 Posts: 89




This query is working fast for short intervals.
Do not use it for intervals with length > 10....
Also, if you want calculate yours integral, you have to change:
Code: 
table (select 3 * power(Xc + step, 2)  2 * (Xc + step) Fc
from sysibm.sysdummy1 ) it 
and
Code: 
Source (Xstart, Xfinish, imgFunc, eps) as
(select double(1), double(12), '3 * X^2  2 * X', double(1.e3)
from sysibm.sysdummy1 
Lenny 

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