How to allocate files dynamically in COBOL?

navit_1980 · Posted: Wed May 06, 2009 11:13 am

Hi,

I have a question on file handling in COBOL. How can we dynamically allocate flat files inside COBOL depending upon logic?

Say for example, I have a huge i/p file and want to split into x number of files using cobol and then process the same in next job or step. If I know the record count will be y and can split into 10 files, then my x = y/10 records which means 10 files are enough. If in case, my i/p comes as z which is way higher than y. then I might need to split into 20 files. so , I want to allocate files dynalically inside cobol to meet this criteria.

Can anyone please help me resolve this?

Also, please share your thoughts on the performance of my program if I have such dynamic allocations.

Thanks for being of great help!
- Beginner.

superk · Posted: Wed May 06, 2009 7:34 pm

Search here for the "ikjtsoev", "bpxwdyn", or "putenv" programs. You'll find a lot of topics with all sorts of different ideas.

navit_1980 · Posted: Thu May 07, 2009 1:46 am

Thanks a lot for this pointer!