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How to allocate files dynamically in COBOL?

 
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navit_1980

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Joined: 04 Jun 2006
Posts: 6
Location: Charlotte, NC

PostPosted: Wed May 06, 2009 11:13 am    Post subject: How to allocate files dynamically in COBOL?
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Hi,

I have a question on file handling in COBOL. How can we dynamically allocate flat files inside COBOL depending upon logic?

Say for example, I have a huge i/p file and want to split into x number of files using cobol and then process the same in next job or step. If I know the record count will be y and can split into 10 files, then my x = y/10 records which means 10 files are enough. If in case, my i/p comes as z which is way higher than y. then I might need to split into 20 files. so , I want to allocate files dynalically inside cobol to meet this criteria.

Can anyone please help me resolve this?

Also, please share your thoughts on the performance of my program if I have such dynamic allocations.

Thanks for being of great help!
- Beginner.
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superk

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Joined: 26 Apr 2004
Posts: 4650
Location: Raleigh, NC, USA

PostPosted: Wed May 06, 2009 7:34 pm    Post subject: Reply to: How to allocate files dynamically in COBOL?
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Search here for the "ikjtsoev", "bpxwdyn", or "putenv" programs. You'll find a lot of topics with all sorts of different ideas.
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navit_1980

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Location: Charlotte, NC

PostPosted: Thu May 07, 2009 1:46 am    Post subject: Reply to: How to allocate files dynamically in COBOL?
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Thanks a lot for this pointer!
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