ISPF macro: problem in defining line variable

maridawson · New User Joined: 24 Jun 2008 Posts: 59 Location: chennai

hi ,
i have written a ispf macro. that macro is for copying specific set of lines from a dataset and to store those lines in some variables. so that i can write these variables to another result dataset.

the problem here is, for the following loop,
COUNT=1
DO RLINE = FIRST TO LAST BY 1
"ISREDIT (JP."COUNT") = LINE "RLINE
COUNT=COUNT+1
END
FIRST and LAST are the line numbers.....
i could not define the variable is jp.count because it is saying... the syntax is wrong ...... how can i define a variable to get all the lines of that dataset into the variables.

maridawson · New User Joined: 24 Jun 2008 Posts: 59 Location: chennai

i have also tried like without '.' ........ like jp"count" ...... but i couldnt get the values back .... since i cannot form a loop for getting the values of
jp1
jp2
jp3
jp4

since if i give jpcount ...... it will be considered as a single variable.....

Marso · Posted: Thu Mar 12, 2009 6:46 pm

Do it the easy way:

Pedro · Posted: Thu Mar 12, 2009 9:27 pm

I prefer starting with zero, otherwise the count is one too many.

Pedro · Posted: Thu Mar 12, 2009 9:29 pm

You might also try using the CUT macro statement followed later by a macro that uses PASTE.

maridawson · New User Joined: 24 Jun 2008 Posts: 59 Location: chennai

thanks marso and pedro...... i got it ..... that was very simple .... how come i didnt get that idea .......