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Need to know about how space is allocated for the file.

 
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bijoybabu83

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Joined: 15 Jan 2007
Posts: 36
Location: Kerala

PostPosted: Fri Dec 26, 2008 9:46 pm    Post subject: Need to know about how space is allocated for the file.
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How is allocation of memory space handled in Mainframe ?

For example if we give the space as :-

space = (80,(10,1),RLSE)

How is space allocations handled for a file which has 80,000,000 records.

I need to know how is the space going to be allocated between primary and secondary.

Can anyone help.
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enrico-sorichetti

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Joined: 14 Mar 2007
Posts: 10327
Location: italy

PostPosted: Fri Dec 26, 2008 10:02 pm    Post subject: Reply to: Need to know about how space is allocated for the
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did You look at the manual ( jcl guide and jcl reference ) ??
everything is explained very clearly
click on the IBM Manuals link at the top of the page
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prashanth1

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Joined: 27 Sep 2006
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Location: Hyderabad

PostPosted: Tue Jan 20, 2009 12:38 pm    Post subject:
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Bijoybabu,

Probably this may help you.


total size of your file will be 6400000000 bytes ( 80,000,000 * 80).

1 track = 53 KB (around)
1Cyl = 832 KB ( around)

Calculate accordingly and allocate the space to avoid SB37 error.
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Robert Sample

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Joined: 06 Jun 2008
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Location: East Dubuque, Illinois, USA

PostPosted: Tue Jan 20, 2009 5:45 pm    Post subject:
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Quote:

1 track = 53 KB (around)
1Cyl = 832 KB ( around)
These numbers depend on using at least somewhat optimal blocking. If the file is unblocked (as implied in the original post of
Quote:
space = (80,(10,1),RLSE)
then the bytes used per track and cylinder go down -- way down.
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