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Sort differently based on value in a particular column


IBM Mainframe Forums -> DFSORT/ICETOOL
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Aneesh

New User


Joined: 30 Sep 2006
Posts: 60

PostPosted: Sat Nov 08, 2008 7:00 pm
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Hi,

I have a file (FB LRECL 280) that has the following fields.
col1 8-12 (5 bytes numeric
col2 132-142 (11 bytes - S9(6).9(3) - positive, negative or zero)
col3 150-175 (26 bytes - timestamp)

The input record can have multiple records for same value of col1. There should be only 1 record in the output file for the same value of col1. For multiple records with same value of col1, there should be only 1 record in the output file, which should be selected as the record with the highest positive value of col2, or the record with the latest date in the col3 value if there is no record with positive value (>0) for col2. For eg:

Code:

Col1    Col2          Col3
12345   +000003.500   2008-10-26 -> record to o/p file
12345   +000001.200   2008-10-20
12345   -000003.500   2008-11-01
     
12346   +000000.000   2008-10-01
12346   -000003.500   2008-10-26 -> record to o/p file
12346   -000001.200   2008-10-20
       
12347   -000000.500   2008-10-10 -> record to o/p file


Is this something that can be easily done through sort?

Thanks,
Aneesh.
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Frank Yaeger

DFSORT Developer


Joined: 15 Feb 2005
Posts: 7129
Location: San Jose, CA

PostPosted: Sat Nov 08, 2008 10:09 pm
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Here's a DFSORT/ICETOOL job that will do what you asked for:

Code:

//S1    EXEC  PGM=ICETOOL
//TOOLMSG DD SYSOUT=*
//DFSMSG  DD SYSOUT=*
//IN DD DSN=...  input file (FB/280)
//OUT DD DSN=...  output file (FB/280)
//TOOLIN DD *
SELECT FROM(IN) TO(OUT) ON(8,5,ZD) FIRST USING(CTL1)
/*
//CTL1CNTL DD *
  INREC IFTHEN=(WHEN=INIT,
          OVERLAY=(281:132,11,SFF,TO=ZD,LENGTH=9)),
        IFTHEN=(WHEN=(281,9,ZD,LE,0),
          OVERLAY=(281:-1,TO=ZD,LENGTH=9))
  SORT FIELDS=(8,5,ZD,A,281,9,ZD,D,150,26,CH,D)
  OUTFIL FNAMES=OUT,BUILD=(1,280)
/*
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Aneesh

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Joined: 30 Sep 2006
Posts: 60

PostPosted: Sun Nov 09, 2008 12:19 am
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Thank you, Frank.
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