[Solved]What's the output of this COBOL Program

rambabu · New User Joined: 18 Apr 2005 Posts: 67

what is the out of the below program?
01 emp
05 eno pic 999.
05 ename z(4).
move 19 to eno.
move emp to ename.
display emp.
display eno.
display ename.

kvivek · New User Joined: 09 May 2005 Posts: 51 Location: Singapore

display emp - 019
display eno - 019
display ename - SPACES

Regards,
Vivek

vel2k8 · Posted: Tue Jun 14, 2005 10:19 am

Vivek,

I think you are wrong.. This should be the answer..

EMP 0190190
ENO 019
ENAME 0190

Thanks
Vel.

kvivek · New User Joined: 09 May 2005 Posts: 51 Location: Singapore

Vel,

You are correct... Sorry I haven't seen "move emp to ename" statement.

Regards,
Vivek

sudheer648 · New User Joined: 23 May 2005 Posts: 97 Location: Chennai

Hi rambabu,

ENO will be 019 b'coz it moves values from right.
ENAME will 0190 b'coz it moves data from left.
EMP it is group item it is printing both eno and ename.