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File count in sort card with todays date and yesterdays date

 
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vel2k8

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Joined: 10 Jun 2005
Posts: 11
Location: Jacksonville

PostPosted: Tue Mar 11, 2008 5:47 pm    Post subject: File count in sort card with todays date and yesterdays date
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Anybody there,

I have a input file with X number of records.

I want a sort out file with the "filename,todays date,record count,yesterdays date".


Thanks
Vel.
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vel2k8

New User


Joined: 10 Jun 2005
Posts: 11
Location: Jacksonville

PostPosted: Tue Mar 11, 2008 5:56 pm    Post subject: Reply to: File count in sort card with todays date and yeste
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Already I am using the following card but I dont know how to create the yesterdays date.

SORT FIELDS=COPY
OUTFIL TRAILER1=('TEST.FILE.NAME ',',',
&DATENS=(4MD),',',COUNT=(M12,LENGTH=10),',',&DATENS=(4MD)),NODETAIL

Thanks
Vel.
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Frank Yaeger

DFSORT Moderator


Joined: 15 Feb 2005
Posts: 7130
Location: San Jose, CA

PostPosted: Tue Mar 11, 2008 9:06 pm    Post subject:
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You can use a DFSORT job like the following to do what you asked for:

Code:

//S1    EXEC  PGM=ICEMAN
//SYSOUT    DD  SYSOUT=*
//SORTIN DD *
RECORD
/*
//SORTOUT DD DSN=&&S1,UNIT=SYSDA,SPACE=(TRK,(1,1)),DISP=(,PASS)
//SYSIN    DD    *
  OPTION COPY
  OUTFIL REMOVECC,
    BUILD=(C'TODAY,''',DATE1,C'''',80:X,/,
           C'YESTERDAY,''',DATE1-1,C'''')
/*
//S2    EXEC  PGM=ICEMAN
//SYSOUT    DD  SYSOUT=*
//SYMNAMES DD DSN=&&S1,DISP=(OLD,PASS)
//SORTIN DD DSN=...  input file
//SORTOUT DD DSN=...  output file
//SYSIN    DD    *
  SORT FIELDS=COPY
  OUTFIL TRAILER1=('TEST.FILE.NAME ',',',
  TODAY,',',COUNT=(M12,LENGTH=10),',',YESTERDAY),NODETAIL
/*
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