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find whether numeric or alpha numeric

 
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rasitha chandran

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Joined: 25 Jan 2008
Posts: 6
Location: chennai

PostPosted: Thu Jan 31, 2008 3:49 pm    Post subject: find whether numeric or alpha numeric
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Hi,

I have a doubt.

For example,

01 a pic x(4).

and a=12,

now my query is if it is numeric it has to perform some action
and if is alphanumeric it has to do some other action. How can i find out that is numeric.
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murmohk1

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Joined: 29 Jun 2006
Posts: 1439
Location: Bangalore,India

PostPosted: Thu Jan 31, 2008 4:17 pm    Post subject:
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rasitha,

Use CLASS condition.
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Phrzby Phil

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Joined: 31 Oct 2006
Posts: 967
Location: Richmond, Virginia

PostPosted: Thu Jan 31, 2008 7:02 pm    Post subject:
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Your initial condition is ambiguous. For Pic X(4), A cannot = 12.

Which is your case?

A = '0012'
A = '12 '

or something else?
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Phrzby Phil

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Joined: 31 Oct 2006
Posts: 967
Location: Richmond, Virginia

PostPosted: Thu Jan 31, 2008 7:05 pm    Post subject:
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I should have shown my choices better to show the two blanks in the quotes:

Code:
A = '0012'
A = '12  '
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NOWAR

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Joined: 20 Feb 2007
Posts: 11
Location: Houthalen, Belgium

PostPosted: Thu Jan 31, 2008 7:21 pm    Post subject:
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Use the statement

Code:
IF A IS NUMERIC
THEN
  <action>
ELSE
  <action>
END-IF
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dick scherrer

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Joined: 23 Nov 2006
Posts: 19270
Location: Inside the Matrix

PostPosted: Thu Jan 31, 2008 10:50 pm    Post subject:
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Hello Rasitha and welcome to the forums,

Quote:
How can i find out that is numeric.
I believe your first task is to define just what is numeric. For example - is a leading blank still numeric?, trailing blank(s)? Should leading blanks be converted to zeros?

Once the rules are defined, implementation can proceed.
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raghumale

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Joined: 21 Feb 2008
Posts: 6
Location: banglore

PostPosted: Fri Feb 22, 2008 12:40 pm    Post subject:
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hi rasitha


ur question is confujion
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vasanthkumarhb

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Joined: 06 Sep 2007
Posts: 276
Location: Bang,iflex

PostPosted: Fri Feb 22, 2008 12:47 pm    Post subject:
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HELLO Raghumale.....



Quote:
ur question is confujion



There is no confusion in this question answer has been given in the previous post. Please refer the previous posts.
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