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RAJESHB4U
New User
Joined: 10 Jul 2006
Posts: 2
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Hi
Can anybody suggest me how to resolve the mentioned issue.
I have a file in the form of a segments and cannot be mapped to a layout, as shown below.
AM04 C2880054109 CCROHAN CDNAIK FOH5526 C91 C100982203 C3001 C61
i need to check for the fild separtor , Ex - I am searching for C2 and if found, i need to move the value untill next separator(CC) i.e 880054109 to a output file varable.
Please suggest me how to procced in this type of scenario.
Thanks & Regards
Rajesh |
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William Thompson
Global Moderator
Joined: 18 Nov 2006
Posts: 3156
Location: Tucson AZ
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| If "C" is the delimiter then UNSTRING is up to the task. |
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RAJESHB4U
New User
Joined: 10 Jul 2006
Posts: 2
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| William Thompson wrote: |
| If "C" is the delimiter then UNSTRING is up to the task. |
Hi,
The given file is a variable file, so reference modification cannot be used and i have more the one occurance of C, but i want only "880054109" from the file, without using many unstring functions
AM04 C2880054109 CCROHAN CDNAIK FOH5526 C91 C100982203 C3001 C61 |
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agkshirsagar
Active Member
Joined: 27 Feb 2007
Posts: 691
Location: Earth
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| Quote: |
The given file is a variable file, so reference modification cannot be used |
Could you please explain why??? |
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dick scherrer
Moderator Emeritus
Joined: 23 Nov 2006
Posts: 19244
Location: Inside the Matrix
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Hello,
Please post the file definition of the file.
You may use reference modification on a variable length record. At this point, i'm not sure that the definition is clear enough to make recommendations.
What should happen if there is a "C2" and there is no "CC" or the "CC" is encountered 100 bytes later?
When you post more of your "rules", we will offer suggestions. |
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Devzee
Active Member
Joined: 20 Jan 2007
Posts: 684
Location: Hollywood
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Your Scenario can be easily handled with SAS program.
Do you want SAS solution? |
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