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shalini bhat
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Joined: 26 Feb 2007
Posts: 4
Location: India
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1.Is the value of COND , stored in a register? IF so, when I say COND=(4,GT), then am I just checking the return code of the previous step or all the steps ?
2.When there is a COND on the job stmt, is the first step in the JCL tested against this condition or is it just ignored |
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muthuvel
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Joined: 29 Nov 2005
Posts: 217
Location: Canada
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Shalini wrote
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| IF so, when I say COND=(4,GT), then am I just checking the return code of the previous step or all the steps ? |
Yes,you are checking the previous step condition code.Let's assume Step 2 has COND=(4,GT),then if step1 returns a code of greater than 4,then the step 2 is bypassed else step is executed.
Shalini wrote:
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| When there is a COND on the job stmt, is the first step in the JCL tested against this condition or is it just ignored |
The first step in the job will not be tested against the condition, since it is a new job. |
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dick scherrer
Moderator Emeritus
Joined: 23 Nov 2006
Posts: 19244
Location: Inside the Matrix
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Hello,
I believe this is incomplete:
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Quote:
IF so, when I say COND=(4,GT), then am I just checking the return code of the previous step or all the steps ?
Yes,you are checking the previous step condition code.Let's assume Step 2 has COND=(4,GT),then if step1 returns a code of greater than 4,then the step 2 is bypassed else step is executed.
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If you are in step5 and step1 issued the condition code, step 5 will be skipped. If steps 2,3&4 do not check the condition code they will execute.
As the COND=(4,GT) does not specify a particular step, the condition codes from all previous steps will be checked (not just the immediately previous step). You could check for particular steps if that was part of the design. |
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udaybarath
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Joined: 10 May 2005
Posts: 7
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Muthuvel wrote
Yes,you are checking the previous step condition code.Let's assume Step 2 has COND=(4,GT),then if step1 returns a code of greater than 4,then the step 2 is bypassed else step is executed.
In the above example:
If step1 returns a code of greater than 4, then the step 2 is bypassed???
No it should execute.........muthuvel small mistake in your explanation. |
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IQofaGerbil
Active User
Joined: 05 May 2006
Posts: 183
Location: Scotland
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The COND parameter is used to specify the return code tests that MVS
will perform to see if a job step will be executed or not.
Before a job step containing a COND= parameter is executed, the system performs the COND parameter test(s) specified against the return codes from all prior job steps (or the steps named on the COND= parameter).
If none of these tests is satisfied, the system executes the job step;
if any test is satisfied, the system skips the job step on which the COND= parameter is coded.
So when step2 has
COND=(4,GT)
If step 1 returns a code of greater than (GT) 4 then I would have thought that this condition has been satisfied? and thus the step will be bypassed,
yes/no? |
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