vicky10001 Warnings : 1 Active User
Joined: 13 Jul 2005 Posts: 136
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The main difference between static and dynamic call is the time at which the load module of a subroutine gets invoked or gets attached to the load module of its main program. To get a better picture, let us take an example.
Let A be the Main Program, and this main program invokes the subroutines X, Y and Z. We would have coded the modules X, Y, Z and would have compiled it before executing A.
Static Call:
Now, a static call to the modules X, Y and Z means attaching the load modules of X, Y, Z to the load module of A. It?s like creating a single pack which contains all the load modules needed to execute a higher level program which calls many other programs. This can be done by specifying the compiler option "NODYAM" while compiling the program.
All the load modules of sub routines are embedded within the load module of the main progam.
Dynamic Call:
A dynamic call to the modules X,Y and Z means that you will not attach the load modules of X,Y, Z to the load module of A. The load modules of X,Y and Z will lie in a separate library and the load module of A will lie in a separate library. You will just refer to the library in which the load modules of X,Y and Z lie, while executing the program A. So when ever the subroutines X or Y or Z are invoked in the program A, the library which is specified will be searched for the load modules. By mistake, if the library of the subroutine does not contain the referred program, the system standard library will be searched. If the program is not found in standard library too, the programs will abend. This can be done by specifying the compiler option "DYNAM" while compiling the program. |
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