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elmister
New User
Joined: 27 Nov 2005 Posts: 14
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Hi, i have the following step in a jcl. The files dont exist, but the step spent 2 minutes in execute this step. Somebody can give me any explanation?, because i dont understand how an simple delete spend a lot time.
//STEP010 EXEC PGM=IDCAMS
//SYSPRINT DD SYSOUT=*
//SYSOUT DD SYSOUT=*
//SYSIN DD *
DELETE %%HLQ.BAT1SBAS.BACKMAE1.D%%ODATE
DELETE %%HLQ.BAT1SBAS.CTLQMAE1.D%%ODATE
DELETE %%HLQ.BAT1SB30.MAEAUXC1.D%%ODATE
DELETE %%HLQ.BAT1SBAS.MAEAUXCC.D%%ODATE
DELETE %%HLQ.BAT1SBAS.ACCRFILE.D%%ODATE
DELETE %%HLQ.BAT1SB90.BACKMAE1.BACKUP.D%%ODATE
DELETE %%HLQ.BAT1SB90.MAEAUXC1.BACKUP.D%%ODATE
DELETE %%HLQ.BAT1SB90.CTLQMAE1.BACKUP.D%%ODATE
DELETE %%HLQ.BAT1SB90.MAEAUXCC.BACKUP.D%%ODATE
DELETE %%HLQ.BAT1SB90.ACCRFILE.BACKUP.D%%ODATE
IF MAXCC=8 THEN SET MAXCC=0
This was the job log for this step.
-- TIMINGS (MINS.)--
JOBNAME STEPNAME RC EXCP CONN TCB SRB CLOCK SERV
PAC0D190 STEP010 00 10 3 .00 .00 .0 191
Thanks very much. |
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dick scherrer
Moderator Emeritus
Joined: 23 Nov 2006 Posts: 19244 Location: Inside the Matrix
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Hello,
My guess is that it spent all of the time searching the catalog. While they did not exist, that they did not exist had to be "discovered". |
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