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Cobol Program-ID: Is it must?

 
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kalaignar_S
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PostPosted: Mon May 22, 2006 5:07 pm    Post subject: Cobol Program-ID: Is it must?
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Hi..

Its necessary to have the program-id as same as the program name or member name?

Thanks
Kalai
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ursprasanna
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PostPosted: Mon May 22, 2006 5:11 pm    Post subject: Re: Cobol Program-ID
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Not mandatory..
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sril.krishy

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PostPosted: Tue May 23, 2006 5:37 pm    Post subject:
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Hi,
You can successfully compile the program if the program-id and the name of the program is diffrent.But you will get the error when you do linking of the job.

I tried in my system and I got the below error.

IEW2648E 5111 ENTRY xxxxx IS NOT A CSECT OR AN EXTERNAL NAME IN THE MODULE.

Where XXXXX is my program name.

Thanks&Regrds
Krishy
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vijayamadhuri

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PostPosted: Tue May 23, 2006 8:20 pm    Post subject: Hello kalaignar_S
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It is not necesary for u r pgm id to be the same as u r pgm name
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humpty
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PostPosted: Thu May 25, 2006 10:39 am    Post subject: Re: Cobol Program-ID
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hi,

it is not mandatory for the program-id and the program name to be same.
in case you need to call the program, then we use the program-id in the calling program. that hardly matters, the two are set to be same only for our convinience and to avoid confusions with two different names for the same program.

thanks
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hikaps14

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PostPosted: Thu May 25, 2006 11:17 am    Post subject: Re: Cobol Program-ID
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Hi,

i think the scene is geting a bit mixed up .

lets take a example .

there is a program-name = A1 (load name is A1)
with its program-id = A2.

there is another program-name = B

program B calls program (A1 or A2) Statically .

there is program C which calls (A1 or A2) Dynamically .


i guess now if any body coulld tell me the exact answers it would be much
better .
( because i was also confused with load name too so plz chk tat option also )

Thanks in advance ,
-Kapil .
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abhishekraghav

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PostPosted: Thu May 25, 2006 1:39 pm    Post subject: Re: Cobol Program-ID
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Kapil

in first case i think there will be no problem because a single load will be created in that case.

while in case of program C. thing matters is the load name for program A1 and A2.

say for A1 you create its load with load name A.
Now, in program C if you want to call program A1 you will be calling it as:

CALL A USING PARAMETERS.



Having program ID different doesn't effect execution because whatever program ID you give in program, it will go in to load name.

say in source of A1, program ID is ABC and you create A1,s load with name A.
now, if you browse load A then you will find program ID (ABC) for program A1 there.

try and check it with a test program.
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humpty
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PostPosted: Thu May 25, 2006 4:42 pm    Post subject:
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hi kapil,

thats what i wanna say, that using two different names for program
name and program-id ultimately traps u into confusions, so please avoid using two different names. though company norms do not allow two different names for program and program-id.

going to your question.
program name is A1 and program-Id is A2.
now the program B will refer to A2 to call the program
and not A2, when a calling program directly gives the program-id,
it means it is being called statically (default).
i.e the procedure division of program B has to coded as
.
.
PROCEDURE DIVISION
.
.
CALL A2
.
.

With static calls statement, the COBOL program and all called programs are part of the same load module. When control is transferred, the called program already resides in storage, and a branch to it takes place


In case of dynamic call the compiler option set to DYNAM.
for the dynamic call teh program-name in the PROGRAM-ID paragraph or ENTRY statement must be identical to the corresponding load module name or load module alias of the load module that contains the program.


i guess it would resolve your confusions.
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humpty
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PostPosted: Thu May 25, 2006 4:44 pm    Post subject:
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hi everyone,

Please go through the following to clarify all your doubts.

Examples: static and dynamic CALL statements
This example shows how you can code static and dynamic calls.

The example has three parts:

Code that uses a static call to call a subprogram
Code that uses a dynamic call to call the same subprogram
The subprogram that is called by the two types of calls
The following example shows how you would code static calls:


PROCESS NODYNAM NODLL
IDENTIFICATION DIVISION.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 RECORD-2 PIC X. (6)
01 RECORD-1. (2)
05 PAY PICTURE S9(5)V99.
05 HOURLY-RATE PICTURE S9V99.
05 HOURS PICTURE S99V9.
. . .
PROCEDURE DIVISION.
CALL "SUBPROG" USING RECORD-1. (1)
CALL "PAYMASTR" USING RECORD-1 RECORD-2. (5)
STOP RUN.
The following example shows how you would code dynamic calls:


DATA DIVISION.
WORKING-STORAGE SECTION.
77 PGM-NAME PICTURE X(8).
01 RECORD-2 PIC x. (6)
01 RECORD-1. (2)
05 PAY PICTURE S9(5)V99.
05 HOURLY-RATE PICTURE S9V99.
05 HOURS PICTURE S99V9.
. . .
PROCEDURE DIVISION.
. . .
MOVE "SUBPROG" TO PGM-NAME.
CALL PGM-NAME USING RECORD-1. (1)
CANCEL PGM-NAME.
MOVE "PAYMASTR" TO PGM-NAME. (4)
CALL PGM-NAME USING RECORD-1 RECORD-2. (5)
STOP RUN.
The following example shows a called subprogram that is called by each of the two preceding calling programs:


IDENTIFICATION DIVISION.
PROGRAM-ID. SUBPROG.
DATA DIVISION.
LINKAGE SECTION.
01 PAYREC. (2)
10 PAY PICTURE S9(5)V99.
10 HOURLY-RATE PICTURE S9V99.
10 HOURS PICTURE S99V9.
77 PAY-CODE PICTURE 9. (6)
PROCEDURE DIVISION USING PAYREC. (1)
. . .
EXIT PROGRAM. (3)
ENTRY "PAYMASTR" USING PAYREC PAY-CODE. (5)
. . .
GOBACK. (7)
(1)
Processing begins in the calling program. When the first CALL statement is executed, control is transferred to the first statement of the PROCEDURE DIVISION in SUBPROG, which is the called program.
In each of the CALL statements, the operand of the first USING option is identified as RECORD-1.

(2)
When SUBPROG receives control, the values within RECORD-1 are made available to SUBPROG; however, in SUBPROG they are referred to as PAYREC.
The PICTURE character-strings within PAYREC and PAY-CODE contain the same number of characters as RECORD-1 and RECORD-2, although the descriptions are not identical.

(3)
When processing within SUBPROG reaches the EXIT PROGRAM statement, control is returned to the calling program. Processing continues in that program until the second CALL statement is issued.
(4)
In the example of a dynamically called program, because the second CALL statement refers to another entry point within SUBPROG, a CANCEL statement is issued before the second CALL statement.
(5)
With the second CALL statement in the calling program, control is again transferred to SUBPROG, but this time processing begins at the statement following the ENTRY statement in SUBPROG.
(6)
The values within RECORD-1 are again made available to PAYREC. In addition, the value in RECORD-2 is now made available to SUBPROG through the corresponding USING operand, PAY-CODE.
When control is transferred the second time from the statically linked program, SUBPROG is made available in its last-used state (that is, if any values in SUBPROG storage were changed during the first execution, those changed values are still in effect). When control is transferred from the dynamically linked program, however, SUBPROG is made available in its initial state, because of the CANCEL statement that has been executed.

(7)
When processing reaches the GOBACK statement, control is returned to the calling program at the statement immediately after the second CALL statement.
In any given execution of the called program and either of the two calling programs, if the values within RECORD-1 are changed between the time of the first CALL and the second, the values passed at the time of the second CALL statement will be the changed, not the original, values. If you want to use the original values, you must save them.
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umeshkmrsh

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PostPosted: Fri May 26, 2006 11:28 am    Post subject:
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sril.krishy wrote:
Hi,
You can successfully compile the program if the program-id and the name of the program is diffrent.But you will get the error when you do linking of the job.

I tried in my system and I got the below error.

IEW2648E 5111 ENTRY xxxxx IS NOT A CSECT OR AN EXTERNAL NAME IN THE MODULE.

Where XXXXX is my program name.

Thanks&Regrds
Krishy



It looks you people have taken the topic to an different track. Let me put it back on the track. The problem is that "Can we have different name for our program load module (pds member name or u may say load module name) and the PROGRAM-ID".

Our problem is: How the LINKER or dynamic LOADER (in case of dynamic call) locates the program and loads it? Does it uses PROGRAM-ID or load module name? Is there a table that maps PROGRAM-ID to the corresponding load module name?

So problem is not static and dynamic call and how they work.

Regards,
Umesh
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abhishekraghav

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PostPosted: Fri May 26, 2006 11:36 am    Post subject:
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Hi umeshkmrsh,

Just check my previouse post. it contains the answer to main question:

"Having program ID different doesn't effect execution because whatever program ID you give in program, it will go in to load."

as well as answer to hikaps14's doubt.

just check and correct me if i am wrong anywhere.

Regards,
Abhishek.
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umeshkmrsh

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PostPosted: Fri May 26, 2006 11:49 am    Post subject:
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Hi Abhishek,

Yes you have tried to explain and it a good explanation too. But I would like to know how a PROGRAM-ID (if used for calling) gets mapped to the load module (which may have different name).

Is there a table that maps both of these?
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abhishekraghav

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PostPosted: Fri May 26, 2006 12:03 pm    Post subject:
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See load name u decide at the link edit time.
for the sake of avoiding confusion we give it same as the program name and same for the program id.

but you can give as u want:
say program or source name is ABC and it has program id as ABCID, OK.

Now you compile and link edit this program and you give loadname as XYZ.

now after creation of load XYZ, if you browse it you will find your program id (ABCID) name for source ABC there in starting of load.
just check it with a sample program. you will get it cleared.


I think no such table is maintained. only program ID goes into load module. and suppose u want to call the program ABC. you must know the load module name, it is XYZ in case of prgram ABC. so you will write it as

CALL 'XYZ'

and in starting i told that for avoiding confusion we take load module name same as program name.
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umeshkmrsh

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PostPosted: Fri May 26, 2006 12:30 pm    Post subject:
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Thanks,

One more doubt: Can't we use program-id to call a program, say:

CALL "ABCID"

?
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abhishekraghav

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PostPosted: Fri May 26, 2006 12:34 pm    Post subject:
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I dont think So, because whatever name u give with CALL it searches that name in to the load library and if it is found there then it executes it.

one of the reason for unique program name and load with same name is this thing only. other wise by mistake u can execute other programs load.
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umeshkmrsh

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PostPosted: Fri May 26, 2006 12:58 pm    Post subject:
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OK,

I got what you want to say.

Just to add to this topic:

PROGRAM-ID does plays role. IN COBOL-II where we can have more than one programs written within a source file (source code). In this way we can have a program say.

PDS member. ABC.

Code:
IDENTIFICATION DIVISION.
PROGRAM-ID. ABC1.
---
---
PROCEDURE DIVISION
----
---- CALL "ABC2"
----
----
IDENTIFICATION DIVISION.
PROGRAM-ID. ABC2.
----
----
PROCEDURE DIVISION.
----
----
END PROGRAM ABC2.

END PROGRAM ABC1.


Will we be having two load modules in this case Or one?
Lets assume we have one load module - named ABCL.

Now:
(1) When we program ABC1 calls ABC2 it uses program-id i.e ABC2.
(2) And if we want to call program ABC1 from some other program we will use load modules name .. i.e "ABCL"

CALL "ABCL".

Correct me if I am wrong.
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abhishekraghav

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PostPosted: Fri May 26, 2006 1:09 pm    Post subject:
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Thanx! for telling this thing. i really didnt knew.
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mf_user
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PostPosted: Fri Jun 02, 2006 5:39 pm    Post subject:
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Guys, what happens if I have four programs (a, b, c, d) with same program-id (a)? Pls explain.

Tx a lot.
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abhishekraghav

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PostPosted: Fri Jun 02, 2006 5:50 pm    Post subject: Re: Cobol Program-ID
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see my previouse posts. it will be clear to you.
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